The car heads east at an average speed of 50 miles per hour from the intersection point towards East. The truck heads east at an average speed of 60 miles per hour from the intersection point towards South.
The distance of car from the intersection point after t hours is
.
The distance of truck from the intersection point after t hours is
.
Since these distances are perpendicular to each other, distance apart d (in miles) at the end of t hours is

Thus the distance apart is 

<u>Given :</u>








<u>Let's Slove :</u><u> </u>



Answer:
Maximum height reached by the ball is 32 meters.
Explanation:
It is given that,
If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :
...........(1)
t is the time taken
s is the height attained as a function of time.
Maximum height achieved can be calculated as :


-16 t + 32 = 0
t = 2 seconds
Put the value of t in equation (1) as :

s = 32 meters
So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.
Answer:
44.08 Volt
Explanation:
N = 8, A = 0.0775 m^2, R = 8.53 ohm, B = 0.222 T, f = 51 Hz
e0 = N B A w
e0 = 8 x 0.222 x 0.0775 x 2 x 3.14 x 51
e0 = 44.08 Volt