Answer:
The force required to push to stop the car is 288.67 N
Explanation:
Given that
Mass of the car, m = 1000 kg
Initial speed of the car, u = 1 m/s
The car and push on the hood at an angle of 30° below horizontal, ![\theta=30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5E%7B%5Ccirc%7D)
Distance, d = 2 m
Let F is the force must you push to stop the car.
According work energy theorem theorem, the work done is equal to the change in kinetic energy as :
![W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)](https://tex.z-dn.net/?f=W%3D%5Cdfrac%7B1%7D%7B2%7Dm%28v%5E2-u%5E2%29F%5Ctimes%20d%3D%5Cdfrac%7B1%7D%7B2%7Dm%28v%5E2-u%5E2%29)
![v = 0](https://tex.z-dn.net/?f=v%20%3D%200)
![Fd\ cos\theta=\dfrac{1}{2}m(u^2) F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N](https://tex.z-dn.net/?f=Fd%5C%20cos%5Ctheta%3D%5Cdfrac%7B1%7D%7B2%7Dm%28u%5E2%29%20%20%20%20%20%20F%3D%5Cdfrac%7B%5Cdfrac%7B1%7D%7B2%7Dm%28u%5E2%29%7D%7Bd%5C%20cos%5Ctheta%7DF%3D%5Cdfrac%7B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201000%5Ctimes%20%281%29%5E2%7D%7B2%5C%20cos%2830%29%7DF%20%3D%20-288.67%20N)
The force required to push to stop the car is 288.67 N
In your question where the ask is to calculate the charge that the small sphere carries which is the mass of it is 441g moving at an acceleration of 13m/s^2 nad having and electric field of 5N/C. So the formula in getting the charge is mutliply the mass and the quotients of Acceleration and the Electric Field so the answer is 1,146.6
Try calculating maybe that would help you
If im not mistaking it is c