Letter D: The amount of sleep a student gets affects student achievement
How many joules of energy are required to run a 100 W light bulb for one day?
<span><span><span>A</span><span>100 </span>joules</span><span><span>B</span>100<span>W </span><span>× </span>24<span>hr </span>joules</span><span><span>C</span>100<span>W </span><span>× </span>24<span>hr </span><span>× </span>60<span>min∕hr </span>joules</span><span><span>D</span>100<span>W </span><span>× </span>24<span>hr </span><span>× </span>60<span>min∕hr </span><span>× </span>60<span>s∕min </span>joules</span></span>
Answer:
it lowers the voltage in homes
Explanation:
this is due to safety reasons as a human cant survive power line voltages which are between 150k and 760k and if you plugged anything short of a piece of 1 inch thick wire not counting insulation it would immediately start smoking and burn the cable.
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Answer:
Electric field, E = 45.19 N/C
Explanation:
It is given that,
Surface charge density of first surface, 
Surface charge density of second surface, 
The electric field at a point between the two surfaces is given by :
E = 45.19 N/C
So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.
