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3 years ago

What is the volume of this bubble when it reaches the surface?

Physics

1 answer:

steposvetlana [31]3 years ago

8 0

Answer:

Volume will be 15 mL. Solution:- If we look at the given information then it is Boyle's law as the temperature is constant and the volume changes inversely as the pressure changes. So, the volume of the air bubble at the surface will be 15 mL.

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Lindsey wants to know if mineral water will make sunflowers grow taller than plain water. In Group A, she pours one cup of miner

Finger [1]

I would go with C but that's just my personal opinion, I chose C because she only did it to group A

8 0

3 years ago

A 10 m long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 30 m/s when a 68

timama [110]

Answer:

v = 30.39 m/s

Explanation:

given,

mass of glider,M = 680 Kg

mass of the skydiver, m = 68 Kg

horizontal velocity,V = 30 m/s

when skydiver releases, velocity,v = 30 m/s

velocity if the glider,v' = ?

use the conservation of momentum

M V = m' v' + m v

m' = 680-68 = 612 Kg

680 x 30 = 612 x v + 60 x 30

612 v = 18600

v = 30.39 m/s

since the skydiver's speed will be the same as before release

The glider should continue to travel at 30.39 m/s since there are no external forces acting on it

5 0

3 years ago

A girl with a mass of 27 kg is playing on a swing. There are three main forces

N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

Mass of the girl, m = 27 kg
Speed of the girl, v = 3 m/s
Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

$T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N$

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0

2 years ago

A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (1.40

leva [86]

Answer:

The work done required on the coin during the displacement is 21.75 w.

Explanation:

Given that,

A coin slides over a friction-less plane i.e friction force = 0.

The co-ordinate of the given point is (1.40 m, 7.20 m).

The position vector of the given point is represented by $1.40 \hat i+7.20 \hat j$ .

The displacement of the coin is

$\vec d=1.40 \hat i+7.20 \hat j$

The force has magnitude 4.50 N and its makes an angle 128° with positive x axis.

Then x component of the force = 4.50 cos128°

The y component of the force = 4.50 sin128°

Then the position vector of the force is

$\vec F=(4.50 cos 128^\circ)\hat i+(4.50 sin 128^\circ)\hat j$

$=-2.77 \hat i+3.56 \hat j$

We know that,

work done is a scalar product of force and displacement.

$W=\vec F.\vec d$

$=(-2.77 \hat i+3.56 \hat j).(1.40 \hat i+7.20 \hat j)$

=(-2.77×1.40+ 3.56×7.20) w

=21.75 w

The work done required on the coin during the displacement is 21.75 w.

6 0

3 years ago

Radioactive isotopes are used to a. determine the absolute age of rocks. c. determine how rocks are formed. b. determine the rel

PolarNik [594]

Hello <span>Mr1guy24

Question: </span><span>Radioactive isotopes are used to?

Answer: Determine the absolute age of rocks (A)

Reason: If we want to know the absolute age of rocks, then we use radioactive isotopes to find this out.

Hope This Helps!
-Chris</span>

8 0

4 years ago

Read 2 more answers