Answer:
jfjcgufnfhfufm TV fifnricnrhkddufnfif km fgkfkvntfmrugrhfifnh r
Answer:
250N
Explanation:
Given parameters:
Time = 4s
Momentum = 1000kgm/s
Unknown:
Force = ?
Solution:
To solve this problem, we use Newton's second law of motion;
Ft = Momentum
F is the force
t is the time
So;
F x 4 = 1000kgm/s
F = 250N
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v.
K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s
Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
Answer: Real image
Explanation:
converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away).
Answer:
t = 4.21x10⁻⁷ s
Explanation:
The time (t) can be found using the angular velocity (ω):
<em>Where θ: is the angular displacement = π (since it moves halfway through a complete circle)</em>
We have:
<u>Where</u>:
<em>v: is the tangential speed </em>
<em>r: is the radius</em>
The radius can be found equaling the magnetic force with the centripetal force:
![qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}](https://tex.z-dn.net/?f=%20qvB%20%3D%20%5Cfrac%7Bmv%5E%7B2%7D%7D%7Br%7D%20%5Crightarrow%20r%20%3D%20%5Cfrac%7Bmv%7D%7BqB%7D%20)
Where:
m: is the mass of the alpha particle = 6.64x10⁻²⁷ kg
q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C
B: is the magnetic field = 0.155 T
Hence, the time is:
![t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7B%5Ctheta%2Ar%7D%7Bv%7D%20%3D%20%5Cfrac%7B%5Ctheta%7D%7Bv%7D%2A%5Cfrac%7Bmv%7D%7BqB%7D%20%3D%20%5Cfrac%7B%5Ctheta%20m%7D%7BqB%7D%20%3D%20%5Cfrac%7B%5Cpi%20%2A%206.64%20%5Ccdot%2010%5E%7B-27%7D%20kg%7D%7B2%2A1.6%20%5Ccdot%2010%5E%7B-19%7D%20C%2A0.155%20T%7D%20%3D%204.21%20%5Ccdot%2010%5E%7B-7%7D%20s%20)
Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.
I hope it helps you!