1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nonamiya [84]
2 years ago
10

a solid metal sphere of radius 3.00m carries a total charge of -5.50. what is the magnitude of the electric field at a distance

from the sphere's center of 0.250m, 2.90m, 3.10m, and 8.00m?
Physics
1 answer:
aivan3 [116]2 years ago
8 0

Answer:

(a) Electric field at 0.250 m is zero.

(b)  Electric field at 2.90 m is zero.

(c) Electric field at 3.10 m is - 5.15 x 10³ V/m.

(d) Electric field at 8.00 m is - 0.77 x 10³ V/m.

Explanation:

Let Q and R are the charge and radius of the solid metal sphere. The solid metal sphere behave as conductor, so total charge Q is on the surface of the sphere.

Electric field inside and outside the metal sphere is :

E = 0 for r ≤ R ( inside )

  = \frac{KQ}{r^{2} } for r > R ( outside )

Here K is electric constant and r is the distance from the center of the metal sphere.

(a) Electric field at 0.250 m is zero as r < R i.e. 0.250 m < 3 m from the above equation.

(b)  Electric field at 2.90 m is zero as r < R i.e. 2.90 m < 3 m from the above equation.

(c) Electric field at 3.10 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 3.10 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{3.10^{2} }

E = - 5.15 x 10³ V/m

(d) Electric field at 8.00 m is given by the relation as r > R :

E = \frac{KQ}{r^{2} }

Substitute 9 x 10⁹ N m²/C² for K, -5.50 μC for Q and 8.00 m for r in the above equation.

E = - \frac{9\times10^{9}\times5.50\times10^{-6}  }{8^{2} }

E = - 0.77 x 10³ V/m

You might be interested in
A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?
Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. So we can use the following suvat equation:

v=u+at

where

v is the  final velocity

u is the initial velocity

a is the acceleration

t is the time elapsed

For the orange in this problem, we have

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2 is the acceleration

Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

v=0+(9.8)(0.75)=7.35 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
2 years ago
How does the direction of friction relate to the direction of motion
lesya692 [45]
 <span>It reacts to the </span>motion<span>. If the mass hanging from the pulley was overwhelmingly heavier than the mass on the ramp, it'll obviously pull the ramp mass up and thus </span>friction<span> would be trying to oppose this and vice versa. </span>
5 0
2 years ago
Compared to a plane gravitational pull on the ground to 7 miles in sky is what
Citrus2011 [14]
When you're in an airplane that's 7 miles up off the ground, the strength of gravity plunges to only 99.6 percent of its strength all the way down on the ground. A big heavy person, who weighs 200 pounds down at the airport, weighs only 199 pounds 4.7 ounces in a plane at the altitude of 7 miles.
4 0
2 years ago
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
3 years ago
4.Give at least three examples from everyday life where an inclined plane is used to reduce the effort force needed to accomplis
olga nikolaevna [1]
1. A wheelchair ramp. Instead of using lifting force on the wheelchair, You use push or pull force on it.

2. A slide. Instead of throwing down an item, It uses gravitational potential energy make an object "move" down the slide.

3.A screw. It's reducing the force by twisting the screw out of something instead of pulling it out. (Sorry about my bad grammar).
5 0
3 years ago
Other questions:
  • A thin ring of charge of radius R lies in the x-y plane and is centered on the z-axis. The linear charge density, l, of the loop
    7·1 answer
  • Which of the following is true concerning atoms?Atoms are made of even smaller substances called subatomic particles
    15·1 answer
  • You will get 50pts and the check mark.
    9·2 answers
  • A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surf
    7·1 answer
  • Consider a point 0.5 m above the midpoint of the two charges. As you can verify by removing one of the positive charges, the ele
    10·1 answer
  • The Strength of an electromagnet can be increased by reducing the number of turns on the wire coil true or false
    7·1 answer
  • Which list places the layers of the sun in the correct order from outermost to innermost?
    12·1 answer
  • _____ are group of tissue working together to perform a certain job.
    9·1 answer
  • What is an Alternative fuel?
    9·2 answers
  • The ________ explains how our solar system probably formed from a giant cloud of gases and dispersed solid particles.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!