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aleksandrvk [35]
3 years ago
11

After simplifying, which expressions are equivalent? Select three options. (3.42 – 1.75) + (235a – 3.95) (2.5a + 1.65) + (3.4a +

4b) 0 (-3.9b + a) + (-1.7b + 4.9a) 0 -0.4b + (6b - 5.9a) O 5.9a - 5.6b​
Mathematics
1 answer:
poizon [28]3 years ago
3 0

9514 1404 393

Answer:

  C, D, E

Step-by-step explanation:

Collect terms. The last three options are all equivalent to ...

  5.9a - 5.6b​

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Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high m
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The question is incomplete. Here is the complete question.

Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical aptitude) to 5 (high musical aptitude). This year's results were shown in the figure below.

The average (mean) aptitude score:

The median aptitude score:

Answer: mean: 2.73

              median: 3

Step-by-step explanation: <u>Mean</u> is the average number of a set of numbers.

The table below shows a frequency of students to each score of the test. To calculate mean with a frequency table, do the following:

mean=\frac{\Sigma (score*frequency)}{\Sigma frequency}

mean=\frac{0*1+1*5+2*0+3*3+4*3+5*3}{1+5+0+3+3+3}

mean = 2.73

<u>Median</u> is the middle term of a set of data.

When there is a frequency table, median is calculated as:

1) First, determine the total number of observations (n).

For this table, n = 15

2) Because n is odd, find the position of the median using:

position=\frac{n+1}{2}

position = 8th

3) The median will be in the 8th position. To find the position, we add the frequencies and in doing so, we notice the position we want is in the score 3 category. So, the median for this frequency table is 3.

<u>Average score</u> of a musical aptitude test is <u>2.73</u> and median is 3

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2 years ago
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Scorpion4ik [409]

Simplify the expression 5(x-3)(x^2+4x+1)

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