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dedylja [7]
3 years ago
10

Dave works for 5 hours double time and he earns $98 find his normal hourly year rate

Mathematics
1 answer:
Finger [1]3 years ago
3 0

Answer: $9.8 per hour

Step-by-step explanation:

If Dave works for 5 hours at double time, then he gets paid for 10 hours of work. If he earned $98 for 10 hours of work, all you need to do is divide the amount of money earned by the hours of work. \frac{98}{10}=9.8 dollars per hour.

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Given the function g(x) = 6^x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
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Section A and B
\frac{36 - 6}{2 - 1}  = 30 \\  \frac{1296 - 216}{4 - 3}  = 1080
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4 years ago
The ordered pairs model an exponential growth function. (−1,21.875), (0,35), (1,56), (2,89.6) What is the function equation? f(x
Karolina [17]

Answer:

Given the ordered pairs, the exponential growth function would be represented by f(x)=35(1.6)^x.

Step-by-step explanation:

Exponential growth functions are represented by the following equation: f(x)=ab^x, where 'a'=initial value; 'b'=rate of growth; 'x'=independent value or time.  Given the points, we see that the values of 'x' increase by 1 each time and dividing two 'y' values (35/21.875; 56/35; 89.6/56) gives us a change of 1.6.  Rate is the change in y/the change in x, or 1.5/1, which is the value of 'b'. When 'x' is equal to 0, the value of 'y' is 35, so this represents the initial value, or 'a'.  Plugging in these values will give us the final equation f(x)=35(1.6)^x.

5 0
3 years ago
Karissa begins to solve the equation (x – 14) + 11 = x – (x – 4). Her work is correct and is shown below. (x – 14) + 11 = x – (x
sdas [7]
Her work is incorrect because she accidentally changed -14 to -7 in the second step.
Working it out from the top we get
(x-14)+11=x-(x-4)
x-14+11=x-x+4
x-3=0+4
Final answer:
x=7
Hope I helped :)
4 0
4 years ago
Read 2 more answers
2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?​
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Answer:

1.25

Step-by-step explanation:

Find the average.

-5.1+7.6=2.5

2.5/2

1.25

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3 years ago
Dilation – stretching or compressing the graph of a function
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Whats the question here?

8 0
3 years ago
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