It would decrease hope this helps
Answer:
compound
Explanation:
MgO is an inorganic compund :) The simplest explanation is that it's not an element b/c there's two elements (Mg & O) in the substance, and it's not a mixture b/c you can't easily separate the two elements.
Becoming an ion involves gaining or losing electrons
Electrons have a relative mass of 0
So adding or removing them doesn't change the mass of the atom
So the answer is (3) remains the same
<u>Answer:</u> The rate of the reaction when concentrations are changed is 
<u>Explanation:</u>
For the given chemical reaction:

The given rate law of the reaction follows:
![\text{Rate}_1=k\frac{[A][C]^2}{[B]^{1/2}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D_1%3Dk%5Cfrac%7B%5BA%5D%5BC%5D%5E2%7D%7B%5BB%5D%5E%7B1%2F2%7D%7D)
We are given:

When the concentrations are changed:
New concentration of A = 2A (Concentration is doubled)
New concentration of C = 2C (Concentration is doubled)
New concentration of B = 3B (Concentration is tripled)
The new rate law expression becomes:
![\text{Rate}_2=k\frac{[2A][2C]^2}{[3B]^{1/2}}\\\\\text{Rate}_2=\frac{2\times 2^2}{3^{1/2}}\times (k\frac{[A][C]^2}{[B]^{1/2}})\\\\\text{Rate}_2=4.62\times (\text{Rate}_1)\\\\\text{Rate}_2=4.62\times 1.12\times 10^{-2}\\\\\text{Rate}_2=5.17\times 10^{-2}M/s](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D_2%3Dk%5Cfrac%7B%5B2A%5D%5B2C%5D%5E2%7D%7B%5B3B%5D%5E%7B1%2F2%7D%7D%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D%5Cfrac%7B2%5Ctimes%202%5E2%7D%7B3%5E%7B1%2F2%7D%7D%5Ctimes%20%28k%5Cfrac%7B%5BA%5D%5BC%5D%5E2%7D%7B%5BB%5D%5E%7B1%2F2%7D%7D%29%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D4.62%5Ctimes%20%28%5Ctext%7BRate%7D_1%29%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D4.62%5Ctimes%201.12%5Ctimes%2010%5E%7B-2%7D%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D5.17%5Ctimes%2010%5E%7B-2%7DM%2Fs)
Hence, the rate of the reaction when concentrations are changed is 