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Lera25 [3.4K]
4 years ago
15

What can scientists measure to provide evidence that electrons can move from one energy level to another

Chemistry
1 answer:
andrey2020 [161]4 years ago
8 0

Answer:

recording the wavelength of light

Explanation:

When an appropriate measure of energy say in the form of light of a certain wavelength, is supplied, electrons have a tendency to absorb the energy and get excited to a higher energy level. Conversely, if an electron is already at a higher energy state it will emit energy in the form of light (or heat) and return to a more stable lower energy state.

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we know from Newton’s 2nd Law of Motion that the force on an object is equal to the mass of the object times the acceleration of
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The acceleration of the ball was 0.6 m·s⁻².

<em>F = ma</em>

<em>a = F</em>/<em>m</em> = 5 N/9 kg × (1 kg·m·s⁻²/1 N) = 0.6 m·s⁻²

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3 years ago
In a neutralization reaction, an aqueous solution of an Arrhenius acid reacts with an aqueous solution of an Arrhenius base to p
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Answer: c. Salt and Water

Explanation:

For example;

When an Arrhenius acid such as; Tetraoxosulphate (VI) acid  (H2SO4) reacts with an Arrhenius base such as Potassium hydroxide (KOH), the products formed in this neutralization reaction is a salt known as ''Potassium Sulphate''  (K2SO4) and ''Water'' (H2O).

H2SO4   +     KOH ------------->   K2SO4      +    H2O

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3 years ago
A chemical bond between atoms with similar electronegatives
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C metallic bond I’m sure that that is the right answer
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3 years ago
An analytical chemist is titrating 242.5mL of a 1.200M solution of hydrazoic acid HN3 with a 0.3400M solution of NaOH . The pKa
fgiga [73]

<u>Answer:</u> The pH of the solution is 12.61

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}       ......(1)

  • <u>For hydrazoic acid:</u>

Molarity of hydrazoic acid solution = 1.200 M

Volume of solution = 242.5 mL

Putting values in equation 1, we get:

1.200M=\frac{\text{Moles of hydrazoic acid}\times 1000}{242.5mL}\\\\\text{Moles of hydrazoic acid}=0.291mol

  • <u>For NaOH:</u>

Molarity of NaOH solution = 0.3400 M

Volume of solution = 1006 mL

Putting values in equation 1, we get:

0.3400M=\frac{\text{Moles of NaOH}\times 1000}{1006mL}\\\\\text{Moles of NaOH}=0.342mol

The chemical reaction for hydrazoic acid and NaOH follows the equation:

                   HN_3+NaOH\rightarrow NaN_3+H_2O

<u>Initial:</u>           0.291        0.342

<u>Final:</u>                  0          0.051                 0.291      0.291

Volume of solution = 242.5 + 1006 = 1248.5 mL = 1.2485 L    (Conversion factor:  1 L = 1000 mL)

  • <u>For NaOH left:</u>

Left moles of NaOH = 0.051 moles

Volume of the solution = 1.2485 L

Putting values in equation 1, we get:

\text{Molarity of NaOH}=\frac{0.051mol}{1.2485L}=0.0408M

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=0.0408M

Putting values in above equation, we get:

pOH=-\log(0.0408)\\\\pOH=1.39

To calculate pH of the solution, we use the equation:

pH+pOH=14\\\\pH=14-1.39=12.61

Hence, the pH of the solution is 12.61

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3 years ago
O2 + 2H2 --&gt; 2H2O in this equation, the O2 is a
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Answer:

this is too easy just do it yourself

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