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Tresset [83]
3 years ago
11

In a graph, what effect would adding a catalyst have on D?

Chemistry
2 answers:
Anika [276]3 years ago
7 0
It would decrease hope this helps
CaHeK987 [17]3 years ago
3 0

Answer:

C. It would stay the same

Explanation:

PLATO answer

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There are around muscles in the human body<br><br> 640<br> 250<br> 100
Gwar [14]
There are 640 muscles in the human body
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4 years ago
A 10.1 g sample of NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. The temperature increases from 23.0 °C to
givi [52]

Hey there!:

moles of NaOH = 10.1 / 40 = 0.2525

heat  = ΔH   x  moles

= 44.4 x 0.2525

= 11.21 kJ

total mass  = 10.1 + 250 = 260.1 g

Q  = m Cp dT

11211    = 260.1 x  4.18 x dT

dT  = 10.3

T2  = 10.3 + 23  = 33.3 °C

temperature = 33.3 ºC°

Hope this helps!

6 0
3 years ago
Read 2 more answers
Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of –7.2°C. Bromine can be classified as a
andreev551 [17]

Answer:

Pure substance.

Explanation:

7 0
3 years ago
Calculate AGrxn for this equation, rounding your
Agata [3.3K]

Answer: \Delta G_{rxn}=130.19J

Explanation:

The balanced chemical reaction is,

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The expression for Gibbs free energy change is,

\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]

\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]

\Delta G_{rxn}=130.19J

Therefore, the gibbs free energy for this reaction is, +130.19 kJ

4 0
3 years ago
Some single cell organisms are similar to blank because they have the ability to blank
Orlov [11]

Explanation:

animals; move

I THINK SO SORRY IF I AM WRONG

5 0
2 years ago
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