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3 years ago

In 3 1/8 hours Aldo reads 7 1/2 chapters. What is the unit rate in chapters per hour ?

Mathematics

1 answer:

geniusboy [140]3 years ago

8 0

Use a calculator

Just look up how to find unit rates and it should be easy

You might be interested in

Give an example of a pair of independent event.

Nutka1998 [239]

(me brushing my teeth) and (you going to school)

3 0

3 years ago

Neveah has created the function of f(x) = 2x+4/3 to represent the growth of her hair, where x represents the number of months si

Andre45 [30]

F(x)=2x+4/3

Replace f(x) by y:
y=2x+4/3

Solving for x:
y-4/3=2x+4/3-4/3

Subtracting the two terms on the left side of the equation:
(3y-4)/3=2x

Dividing both sides of the equation by 2:
[(3y-4)/3]/2=2x/2
[(3y-4)/3]*(1/2)=x
[(3y-4)*1]/[(3)*(2)]=x
(3y-4)/6=x
x=(3y-4)/6

Replace "x" by "f^(-1) (x)" (inverse function) and "y" by "x":
f^(-1) (x) = (3x-4)/6 Inverse function

Then, for x=6
f^(-1) (6) = [ 3(6)-4]/6
f^(-1) (6) = (18-4)/6
f^(-1) (6)= 14/6
f^(-1) (6) = 7/3

Her hair will have grown 6 after 7/3 = 2.33 months

3 0

3 years ago

A recipe calls for 1 /4 start fraction, 1, divided by, 4, end fraction cup of chocolate chips for each batch of cookies. A

Neko [114]

Answer:

Step-by-step explanation:

1/2 cup = 2/4 cups = 2 × 1/4 cup

Alonzo can make 2 batches that each require 1/4 cup.

6 0

2 years ago

A cell phone plan costs $200 to start. Then there is a $50 charge each month. Is there a proportional relationship between time

xxMikexx [17]

Answer:

Step-by-step explanation:

The equation is

y = 200+50x

This is not a proportional relationship because it does not go through the origin

If x=0, y does not equal 0

8 0

3 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

2 years ago