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4 years ago

What species has the electron configuration [ar]3d2?

Physics

2 answers:

Brrunno [24]4 years ago

8 0

The given configuration is : [Ar]3d²

The inner shells of this species has the noble gas, Argon (Ar) configuration while its valence configuration is 3d².

Now the atomic number of Argon = 18

Therefore, the species will have an atomic number = 18 + 2 = 20

Based on the periodic table the species with atomic number 20 is calcium

Ca = [Ar] 3d²

soldier1979 [14.2K]4 years ago

7 0

Answer:

Explanation:

The electronic configuration of the Argon (Ar) has atomic number 18 with all its layers filled

To fill the 3d2 level, you must first fill the 4s level with its two electrons, since it has less energy so the electronic configuration of the atom would be

[Ar] 4s² 3d² corresponding to Titanium

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3 years ago

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Answer:

a) Speed of the particle at this instant

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b) Speed of the particle at (1/8) revolution later

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Explanation:

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Where:

$a_{T}$ : total acceleration, (m/s²)

$a_{n}$ : normal acceleration, (m/s²)

$a_{t}$ : tangential acceleration, (m/s²)

$\alpha$ : angular acceleration (rad/s²)

r : radius of the circular path (m)

v : tangential velocity (m/s)

ω : angular speed ( rad/s)

ω₀: initial angular speed ( rad/s)

θ : angle that the particle travels (rad)

Data:

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$a_{t}$ = 12 m/s²

r=7.90 m :radius of the circular path

Problem development

In the formula (1) :

$a_{n} = \sqrt{(a_{T})^{2} -(a_{t})^{2} }$

We replace the data

$a_{n} = \sqrt{(15)^{2} -(12)^{2}}$

$a_{n} = 9 \frac{m}{s^{2} }$

We use formula (2) to calculate v:

$9 = \frac{v^{2} }{7.9}$ Equation (1)

a)Speed of the particle at this instant

in the equation (1):

$v=\sqrt{9*7.9} = 8.43 \frac{m}{s}$

b)Speed of the particle at (1/8) revolution later

We know the following data:

θ =(1/8) revolution=( 1/8) *2π= π/4

$a_{t}$ = 12 m/s²

v₀= 8.43 m/s

r=7.9 m

We use formula (3) to calculate α

$12 = \alpha *7.90$

$\alpha =\frac{12}{7.9} = 1.52 \frac{rad}{s^{2} }$

We use formula (4) to calculate ω₀

v₀= ω₀ *r

8.43 = ω₀*7.9

ω₀ = 8.43/7.9 = 1.067 rad/s

We use formula (5) to calculate ω

ω² = ω₀² + 2*α*θ

ω²= (1.067)² + 2*1.52*π/4

ω² =3.526

ω = 1.87 rad/s

We use formula (4) to calculate v

v= 1.87 rad/s * 7.9m

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