Answer:
Total area of the two rooms = (width1length1) + (width2length2)
Step-by-step explanation:
The area of the rectangular shape is given by = Length * breadth
Therefore the area of the two rooms can be calculated using the above formula when the variables lengths and widths are given.
Area 1= Area of the first room = length * breadth= (width1length1)
Area 2=Area of the second room = length * breadth= (width2length2)
Total area of the two rooms = Area1 + Area 2
= (width1length1) + (width2length2)
Answer:
p = 308
Step-by-step explanation:
First 3 terms are a^2 + n a^(n-)1 b + n(n-1)/2 * a^(n-2) b^2
So q^2 / pr = (n^2 * a^(2n-2) * b^2 ) / (1/2 * a^n * (n(n-1) * a^(n-2) * b^2 )
= n^2 * a^2n-2 * b^2
-----------------------------------
1/2 n(n-1) * a^(2n-2) * b^2
= 2n / n - 1 as required
given p = 4, q=32 and r = 96:-
32^2 / 4*96 = 2n / n-1
2n / n-1 = 8/3
6n = 8n - 8
2n = 8
n = 4 answer
10 wins/ 6 losses= 1.667
13 wins/ 7 losses= 1.857..
32 wins/ 18 losses= 1.77..
6 wins/ 3 losses= 2
The last team has the highest win to loss ratio, and therefore has the highest winning percentage.
Final answer: Last team, 6 wins and 3 losses
