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o-na [289]
3 years ago
12

-5m-2 (1-7m) show work please

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

9m - 2

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out expression

-5m - 2(1 - 7m)

Step 2: Distribute -2

-5m - 2 + 14m

Step 3: Combine like terms

9m - 2

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Using the Addition Method, solve for y in the following system of linear equations: 4x – 2y = 6 2x + y = 7
Lady_Fox [76]

Answer:

y = 2

Step-by-step explanation:

Addition Method:

4x - 2y = 6

2x + y = 7

-2(2x + y) = -2(7)

4x - 2y = 6

-4x - 2y = -14

-4y = -8

y = 2

Substitution Method:

4x - 2y = 6

2x + y = 7

-2y = 6 - 4x

2y = 4x - 6

y = 2x - 3

2x + (2x - 3) = 7

4x - 3 = 7

4x = 10

x = 2.5

2(2.5) + y = 7

5 + y = 7

y = 2

Brainliest, please :)

4 0
2 years ago
A zoo keeper used 15 bags of acacia leaves to feed the giraffes and 8 bags of eucalyptus leaves to feed the koalas. Write a rati
8090 [49]

Answer: 15:8

Step-by-step explanation:

Acacia leaves= 15 bags

Eucalyptus leaves=8 bags

A ratio compares two amounts and uses a :

We are comparing acacia leaves bags to eucalyptus leaves bags

So-

15:8

We cannot simplify any more, so keep 15:8.

4 0
3 years ago
Five thousand tickets are sold at​ $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded a
aksik [14]

Answer:

the expected value of this raffle if you buy 1​ ticket = -0.65

Step-by-step explanation:

Given that :

Five thousand tickets are sold at​ $1 each for a charity raffle

Tickets are to be drawn at random and monetary prizes awarded as​ follows: 1 prize of ​$500​, 3 prizes of ​$300​, 5 prizes of ​$50​, and 20 prizes of​ $5.

Thus; the amount and the corresponding probability can be computed as:

Amount                            Probability

$500 -$1 = $499                1/5000

$300 -$1 = $299                3/5000

$50 - $1 = $49                     5/5000

$5 - $1 = $4                      20/5000

-$1                                   1- 29/5000 = 4971/5000

The expected value of the raffle if 1 ticket is being bought is  as follows:

E(x) = \sum x  * P(x)

E(x) = (499 * \dfrac{1}{5000} + 299 *\dfrac{3}{5000} + 49 *\dfrac{5}{5000} + 4 * \dfrac{20}{5000}  + (-1 * \dfrac{4971}{5000} ))

E(x) = (0.0998 + 0.1794+0.049 + 0.016  + (-0.9942 ))

E(x) = (0.3442 -0.9942 )

\mathbf{E(x) = -0.65}

Thus; the expected value of this raffle if you buy 1​ ticket = -0.65

7 0
3 years ago
Suppose you invest $400 at an annual interest rate 7.6% compounded continuously. How much will you have in the account after 1.5
goldfiish [28.3K]
\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$400\\
r=rate\to 7.6\%\to \frac{7.6}{100}\to &0.076\\
t=years\to &1.5
\end{cases}
\\\\\\
A=400e^{0.076\cdot 1.5}\implies A=400e^{0.114}
3 0
3 years ago
Can you simplify 846/1000
OverLord2011 [107]
Yes, the simplified fraction would 423/500
8 0
3 years ago
Read 2 more answers
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