The relationship between the amount of data downloaded d, in megabytes, and the time t, in seconds, after the download started i
s shown.
Which of the following statements are true? Select all that apply.
A. The data points on the scatter plot suggest a linear association.
B. The data points on the scatter plot suggest a quadratic association.
C. The data points on the scatter plot suggest a positive association.
D. The data points on the scatter plot suggest a negative association.
E. For every second that passes, about 1 additional megabyte is downloaded.
F. For every second that passes, about 0.5 additional megabyte is downloaded.
G. The function that represents the line of best fit is approximately d(t) = 0.51t - 1.64.
H. The function that represents the line of best fit is approximately d(t) = 1.04t + 0.51.
Which of the following statements are true? Select all that apply.
A. The data points on the scatter plot suggest a linear association.
B. The data points on the scatter plot suggest a quadratic association.
C. The data points on the scatter plot suggest a positive association.
D. The data points on the scatter plot suggest a negative association.
E. For every second that passes, about 1 additional megabyte is downloaded.
F. For every second that passes, about 0.5 additional megabyte is downloaded.
G. The function that represents the line of best fit is approximately d(t) = 0.51t - 1.64.
H. The function that represents the line of best fit is approximately d(t) = 1.04t + 0.51.
2 answers:
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Range:[-2,8)
That’s the range for the domain down below
That’s the range for the domain down below
Answer:
c = 15d + 30
Step-by-step explanation:
Hey there!
This can be represented by an equation of a line, where the number of days is our x-values(d), and the price is our y-values(c).
The price for one day ($45) and the price for 4 days($90) are specific points on that line.
The points are (1, 45) and (4, 90).
We can first find the slope of the line:
- As the price rises 45, the days increase by 3
- Slope = rise/run
- Slope = 45/3
- Slope = 15
Now we can find the base price, by plugging the slope and a point into the equation y = mx + b.
Solve for b:
- y = mx + b
- 45 = 15(1) + b
- 45 = 15 + b
- 30 = b
The base price (b) is 30.
The equation is