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Dvinal [7]
3 years ago
14

Which equation can be used to find the perimeter of the rectangular chalkboard

Mathematics
1 answer:
Alik [6]3 years ago
4 0

If the chalkboard is just rectangular we can just use:

(2 x L) + (2 x W)

or

L+L+W+W

L= Length

W= Width

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I need to figure out what x is for my homework and I’m so confused teehee.
garik1379 [7]

Answer:

x = 9

Step-by-step explanation:

set a proportion: 8/12 = 6/x => 8x = 72 => x = 9

3 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
How do I find the value of y in y=mx+c
Fofino [41]
Plug in your coefficients
3 0
3 years ago
What is y? i am having trouble figuring out what y is
Andre45 [30]

Answer:

\sf \boxed{\bf y =5\sqrt{22}}

Step-by-step explanation:

<h3>45° - 45° - 90° triangle:</h3>

       The ratio of sides of 45 - 45 - 90 triangle is  a : a : a√2.

a is the side opposite to 45°.

From the figure, a = 5√11

The side opposite to 90° is a√2.

y = a√2

  \sf = 5\sqrt{11} * \sqrt{2}\\\\   = 5*\sqrt{11*2}\\\\   = 5\sqrt{22}

8 0
1 year ago
On the coordinate plane, Kyle graphs a line that represents a proportional relationship between x and y
goldenfox [79]

Option D) (0, 0)

<h2>Explanation:</h2>

The complete question is:

_______________________________________

On the coordinate plane, Kyle graphs a line that represents a proportional relationship between x and y. Which point MUST be on the line?

A) (0, 1)

B) (1, 0)

C) (1, 1)

D) (0, 0)

_______________________________________

A proportional relationship between x and y can be written in a mathematical language as follows:

y=kx

For any non-constan k-value. As you can see, this k-value represents the slope of a line. Remember that the Slope-intercept form of a line is given by:

y=mx+b \\ \\ m:Slope \\ \\ b:y-intercept

In the case of y=kx the y-intercept is zero, so the line passes through.

In conclusion, <em>Kyle's graph is a line that represents a proportional relationship between x and passes through point (0, 0)</em>

<h2>Learn more:</h2>

Direct variation: brainly.com/question/13881905

#LearnWithBrainly

7 0
3 years ago
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