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Soloha48 [4]
3 years ago
8

How many solutions does 3x-1=3 have?

Mathematics
2 answers:
goblinko [34]3 years ago
8 0

Answer:

One solution

Step-by-step explanation:

3x=4

x=4/3

no other answer

USPshnik [31]3 years ago
4 0

Answer:

one solution

Step-by-step explanation:

3x-1=3

Add 1 to each side

3x-1+1=3+1

3x = 4

Divide by 3

3x/3 = 4/3

x = 4/3

There is one solution

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Which expressions are equivalent to (5g+3h+4) . 2
Elza [17]

Answer:

2(5g+3h+4)

10g+6h+8

Please that is the answer

3 0
3 years ago
Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.
Serggg [28]
Same here, we do a quick switcharoo on the variables first,

\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5
\\\\\\
x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y
6 0
3 years ago
How does the Counting Principle help when determining the sample space for a probability distribution?
andreyandreev [35.5K]

Answer:

This is also known as the Counting rule.

The Fundamental Counting Principle is used in determining all the possible outcomes and the total possible ways different events can be combined with each other. It is usually done by multiplying all the events together to get the total possible outcome. Doing this also helps in determining the sample space of a probability.

For example there are events a, b and c. The total sample space or possible outcome will be a*b*c.

7 0
3 years ago
Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2
ololo11 [35]

Answer:

The solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

y=6x-3\\y=x-2

Solving:

Let:

y=6x-3--eq(1)\\y=x-2--eq(2)

Put value of y from equation 2 into equation 1

y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}

Now, put value of x in equation 2 to find value of y

y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}

So, the solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

7 0
3 years ago
Please help asap! Due tonight!
oksano4ka [1.4K]

Answer:

Second choice, 3

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + b^2 = 5^2

16 + b^2 = 25

b^2 = 9 (square root both sides)

b = 3

7 0
3 years ago
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