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Neporo4naja [7]
2 years ago
6

Which values are solutions to the inequality below? Check all that apply

Mathematics
2 answers:
Masja [62]2 years ago
7 0

Answer: b, c, e

Step-by-step explanation:

Lelu [443]2 years ago
7 0
It’d be the answers B, C, E
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Yep here we go again:
Shtirlitz [24]

Answer:

9 am it will be IV quadrant

11 it will be I quadrant

hope it helps u

5 0
3 years ago
Read 2 more answers
Find the value of x. Then the measure of each angle
Shtirlitz [24]
The interior angles of a triangle must add to 180 degrees.

110+5x+2x=180
110+7x=180
7x=70
x=10

Then plug in the x value into each angle expression
5(10)=50 degrees
2(10)=20 degrees
4 0
3 years ago
the temperature of the water in Emily's fish tank was 78 degrees F on Sunday the water temperature was changed by -3 on Monday a
SpyIntel [72]

To solve this problem, let us analyze this step by step. The temperature for each day is as follows:

 

Water temperature on Sunday = 78 degrees F

Water temperature on Monday = changed by -3 degrees F

Water temperature on Tuesday = changed by 3 degrees F

 

We can see that the total change of water temperature from Sunday to Tuesday is:

-3 + 3 = 0

Therefore there is zero overall change. There the integer which represents the temperature change is “0”.

 

Since the overall change in water temperature is zero, hence the temperature on Sunday and on Tuesday is similar.

Water temperature on Tuesday = 78 degrees F

8 0
3 years ago
Not sure how I would do this any buddy can help me
Alinara [238K]
I beilive the answer to that is niether.


hope this helped!
4 0
3 years ago
Read 2 more answers
A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in​ ft/s. The rang
VARVARA [1.3K]

Answer:

\theta=24.4^\circ

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range​ of a projectile is in reality approximated by the equation x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta), where we will use ft for distances.

From the given equation we have then \frac{x32ft/s^2}{v^2} =sin(2\theta), which means \theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2} since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and  v = 85 ft/s, we can substitute these values from the equation written, and we will have \theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}, and from now on we have just to use a calculator, obtaining \theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ

3 0
3 years ago
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