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3 years ago

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g The fundamental premise of simple harmonic motion is that a force must be proportional to an object's displacement. Is anythin

g else required? Simple harmonic motion also requires that the displacement point be in a direction that is equal to the force. Simple harmonic motion also requires that the spring be made of metal. Simple harmonic motion also requires that the displacement point be in a direction that is opposite to the force.

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

c) True. the displacement point be in a direction that is opposite to the force.

Explanation:

The simple harmonic movement movement requires that the force be proportional to the displacement.

It also requires that the force be restorative, that is, the force is in the opposite direction of movement

Let's review the statements of the exercise

a) False. The movement creates and does not stop

b) False. If it is not of a metal, only the spring constant changes

c) True. This force is what creates a swing

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En la figura los émbolos son de masa despreciable y están en reposo, como se ve en la figura, siendo M=300 kg. Determine: a) la

Leni [432]

The image mentioned is in the attachment

Answer: a) P = 2450 Pa;

b) P = 2940 Pa;

c) F = 4.9 N

Explanation:

a) Pressure is a force applied to a surface of an object or fluid per unit area.

The image shows a block applying pressure on the large side of the piston. The force applied is due to gravitation, so:

P = $\frac{F}{A}$

P = $\frac{m.g}{A}$

P = $\frac{300.9.8}{1.2}$

P = 2450 Pa

The pressure generated by the block is P = 2450 Pa.

b) A static liquid can also exert pressure and can be calculated as:

$P_{staticfluid} =$ ρ.g.h

where

ρ is the density of the fluid

h is the depth of the fluid

g is acceleration of gravity

$P_{staticfluid} =$ 600.9.8.0.5

$P_{staticfluid} =$ 2940 Pa

The pressure in the fluid at 50 cm deep is $P_{staticfluid} =$ 2940 Pa.

c) For the system to be in equilibrium both pressures, pressure on the left side and pressure on the right side, have to be the same:

$P_{s} = P_{b}$

$\frac{F}{A_s}$ = $\frac{F_b}{A_b}$

F = $\frac{F_b}{A_b}.A_s$

Adjusting the units, $A_{s}$ = 0.002 m².

F = $\frac{300.9.8.0.002}{1.2}$

F = 4.9 N

The force necessary to be equilibrium is F = 4.9 N.

4 0

3 years ago

Ship A is 32 miles north of ship B and is sailing due south at 16 mph. Ship B is sailing due east at 12 mph. At what rate is the

Zielflug [23.3K]

Answer:

$\dfrac{dz}{dt} =-5.6\ mile/h$

Explanation:

distance between ship A and B = 32 mile

Ship A velocity in south, dx/dt = -16 mph

Ship B is sailing toward east with speed, dy/st = 12 mph

time = 1 hour

rate of change of distance between them = ?

x be the distance travel after t time

X = 32 + x

Let distance between them be z

now, using Pythagoras theorem to calculate distance between ships after 1 hours

z² = x² + y²

z² = (32 + x)² + 12²

z² = (32 - 16)² + 12²

z = √400

z = 20 miles

now, calculation of rate of change of distnace

z² = (32 + x)² + y²

differentiating both side w.r.t. time

$2 z \dfrac{dz}{dt} = 2(32+x)\dfrac{dx}{dt} + 2 y\dfrac{dy}{dt}$

$z \dfrac{dz}{dt} =(32-16)\dfrac{dx}{dt} +y\dfrac{dy}{dt}$

$20\times \dfrac{dz}{dt} =16\times (-16) +12\times 12$

$\dfrac{dz}{dt} =\dfrac{-112}{20}$

$\dfrac{dz}{dt} =-5.6\ mile/h$

hence, the rate is the distance between them changing at the end of 1 hour is equal to $\dfrac{dz}{dt} =-5.6\ mile/h$

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3 years ago

Your car is stalled in the middle of a large patch of ice (assumed to be frictionless). You have a friend that has thrown a rope

Gnoma [55]

Answer:

The time depends on the distance that they have to travel

$x(t) = \frac{0.3846t^{2} }{2}$

Explanation:

The only horizontal force exerts over the car and you, it is the force that your friend is applied

Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus

$\sum{F} = ma$

550 = 1430a

a = 0.3846 m/s2

The car and you have a motion under constant acceleration, then theirs position to a time-based is:

$x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}$

By the initial conditions

$x(t) = \frac{at^{2} }{2}$

$x(t) = \frac{0.3846t^{2} }{2}$

The time depends on the distance that they have to travel

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4 years ago

Someone pls answer this

andriy [413]

Answer:

<em>The speed of metal block B is 5 m/s after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of them all

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, we have:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting the given values:

$\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}$

$\displaystyle v'_2=\frac{8}{1.6}$

$\displaystyle v'_2=5\ m/s$

The speed of metal block B is 5 m/s after the collision

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3 years ago

Why is the HR diagram important to scientists?

katovenus [111]

A. yeah is A. i bet my wifes life on

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3 years ago

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