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Burka [1]
3 years ago
6

What influences the path that surface currents take?

Physics
2 answers:
polet [3.4K]3 years ago
4 0
For the answer to the question above asking <span>What influences the path that surface currents take?</span>
It's the force of the wind that influences the path of surface currents.
I hope my answer helped you. feel free to ask more questions. Have a nice day!
IceJOKER [234]3 years ago
4 0

Hello,

The answer is....

Wind Forces and Earth Rotation

The influences of the path that surface currents take is Wind Forces and Earth Rotation.

Hope this helps!!!! :)

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A force of 100 newtons Is applled to a box at an angle of 36° with the horizontal. If the mass of the box Is 25 kilograms, what
faust18 [17]
Horizontal component of force = 100cos(36)= 80.9 N
5 0
2 years ago
You place the spring vertically with one end on the floor. You then lay a 1.60 kg book on top of the spring and release the book
malfutka [58]

Answer:

Compression in the spring, x = 3.7 cm

Explanation:

It is given that,

Mass of the book, m = 1.6 kg

It can be assumed the spring constant of the spring is, k = 840 N/m

As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :

\dfrac{1}{2}kx^2=mgx

x=\dfrac{2mg}{k}

x=\dfrac{2\times 1.6\ kg\times 9.8\ m/s^2}{840\ N/m}  

x = 0.037 meters

or

x = 3.7 cm

So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.

4 0
2 years ago
What is the average time in days between moon phases?.
podryga [215]

Answer:

28

Explanation:

There is a 28 day cycle of the moon phase as it rotates on earths axis.

4 0
1 year ago
Use the diagram below to answer the following question:
d1i1m1o1n [39]

Answer:

3.0 cm

Explanation:

We can solve this problem by using the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length of the mirror

p is the distance of the object from the mirror

q is the distance of the image from the mirror

In this problem we have:

f = 1.5 cm is the focal length of the mirror (positive for a concave mirror)

p = 3.0 cm is the distance of the object from the mirror

Therefore, the distance of the image is:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{1.5}-\frac{1}{3.0}=\frac{1}{3.0}\\\rightarrow q=3.0 cm

And the positive sign means that the image is real.

(The second part of the exercise is just the description of the image of the first exercise).

5 0
2 years ago
An applied force of 50 N is used to accelerate an object, that weighs 73 N, to the right across a frictional surface. The object
Hunter-Best [27]

Answer:

5.38 m/s^2

Explanation:

NET force causing the object to accelerate  =  50 -10 = 40 N

Mass of the object =  73 N / 9.81 m/s^2 = 7.44 kg

F = ma

40 = 7.44 * a         a = 5.38 m/s^2

6 0
1 year ago
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