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AleksAgata [21]
4 years ago
7

11. A 3.8 kg object is lifted 12 meters. Approximately how much work is performed during the lifting?

Physics
1 answer:
Mademuasel [1]4 years ago
4 0
Hope this answers your question!! Ask any help at anytime
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Water can form large dewdrops in nature how would droplets made of vegetable oil instead of water be different
Natasha2012 [34]

Answer:d

Explanation: oil would form droplets but only tiny ones because it’s surface tension is lower than that of water

3 0
3 years ago
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The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

      = 2.21074 x 10500

      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0
3 years ago
a box with a weight of 555 N is sitting on the ground and the bottom of the box measures 0.55 m by 0.45. What is the pressure ex
IrinaK [193]

Explanation:

Pressure = force / area

P = 55 N / (0.55 m × 0.45 m)

P = 220 Pa

8 0
3 years ago
Unlike a physical change, a chemical change is not easily what?
krok68 [10]

because a chemical change takes time

8 0
3 years ago
A girl pushes her little brother on his sled with a force of 200. N for 850. m. How much work is this iſ the fored
Eddi Din [679]

Explanation:

Given that,

A girl pushes her little brother on his sled with a force of 200. N for 850. m

We need to find the work done by the force of friction acting on the sled. The force of friction is 200 N

Net force = 200 N - 200 N = 0

Work done = 0

If force of friction is 300 N.

Net force = 300 N - 200 N = 100 N

The work done by a force is given by :

W = Fd

Put values,

W = 100 × 850

W = 85000 J

Hence, this is the required solution.

5 0
3 years ago
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