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Leto [7]
3 years ago
6

The focal length of the lens of a simple digital camera is 40 mm, and it is originally focused on a person 25 m away. In what di

rection must the lens be moved to change the focus of the camera to a person 4.0 m away
Physics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

Explanation:

Here image distance is fixed .

In the first case if v be image distance

1 / v - 1 / -25 = 1 / .05

1 / v = 1 / .05 - 1 / 25

= 20 - .04 = 19.96

v = .0501 m = 5.01 cm

In the second case

u = 4 ,

1 / v - 1 / - 4 = 1 / .05

1 / v = 20 - 1 / 4 = 19.75

v = .0506 = 5.06 cm

So lens must be moved forward by 5.06 - 5.01 =  .05 cm ( away from film )

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Answer:

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Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t
Lady_Fox [76]

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3 years ago
To ancient peoples, why were planets special?
coldgirl [10]

Answer:

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7 0
2 years ago
An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
lakkis [162]

Answer: 1.55 x 10⁴ Nm²c^-1

Explanation: The electric flux, electric field intensity and area are related by the formulae below.

Φ= EAcosθ,

Where Φ= electric flux (Nm²c^-1)

E =electric field intensity (N/m²)

A = Area (m²)

θ= this is angle between the planar area and the magnetic flux

For our question E=3.80KN/c= 3800 N/c

A= 0.700 x 0.350= 0.245m²

θ= 0° ( this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

Hence Φ= 3800 x 0.245 x cos(0)

= 3800 x 0.245 x 1 (value of cos 0° =1)

= 1.55 x 10⁴ Nm²c^-1

Thus the electric field is 1.55 x 10⁴ Nm²c^-1

4 0
3 years ago
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Alchen [17]
So 10 gallons of gas would let you travel 300 Miles. 

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After that, the warning light turns ON! 

Hope this helps!!
7 0
2 years ago
Read 2 more answers
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