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muminat
3 years ago
8

A person riding on a bus hears the horn of a car that the bus is approaching. After the bus passes the car and is traveling away

from it, the bus rider hears the car horn again. Choose the best description of the new sound heard by the bus rider.
A. The car horn will sound the same, not higher or lower than it did before.
B. The car horn will sound higher in frequency than it did before.
C. The car horn will sound lower in frequency than it did before.
Physics
1 answer:
Grace [21]3 years ago
4 0

Answer:

option (c)

Explanation:

According to the doppler's effect, the frequency of sound decreases.

If there is a relative motion between the source and the observer, the frequency of sound changes apparently.

the formula of the doppler effect is given by

f' =\frac{v-v_{o}}{v}}f

where, f is the real frequency, v be the speed of sound, vo be the speed of the observer, here, the bus is the observer.

So, the value of f' < f

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Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
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7 0
4 years ago
A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows
Alona [7]

Answer:

1) The girl's acceleration at time 't' is, a=0.47 m/s²

2) The girl's acceleration at time 't₁' is, a_{1}=0 m/s²

3) The girl's acceleration at time 't₂' is,  a_{2}=-0.14 m/s²

Explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'

                                a=\frac{v-u}{t}

                                a=\frac{1.4-0}{3}

                               a=0.47 m/s²

2) The girl's acceleration at time 't₁'

                                a_{1} =\frac{v_{1} -v}{t_{1}}

                                a_{1}=\frac{1.4-1.4}{6}

                               a_{1}=0 m/s²

3) The girl's acceleration at time 't₂'

                                a_{2} =\frac{v_{2} -v_{1}}{t_{2}}

                                a_{2}=\frac{0-1.4}{10}

                               a_{2}=-0.14 m/s²

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3 years ago
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3 years ago
A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magn
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Answer:

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F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}

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