Answer:
a. L =3.465 J.s
b. 3.186 rad/s
c. T = 1.972 s
d. Lp = 0.022 J.s; up or down, depending on the direction of L
Explanation:
(a)We have the formula for angular momentum as
L = I*w where I = moment of inertia = 
L = 
(b) ω = M*g*D/L
where D = L/2 = 0.96/2 = 0.48m
ω = (23* 0.48/3.465) rad/s = 3.186 rad/s
(c) T = 2π/ω
T = 2*π/3.186 s = 1.972 s
(d) Lp = 
Solving with mass M, D and angular velocity ω
Lp = 0.022 J.s; up or down, depending on the direction of L
Answer:
T=7.4 N hence T<30 N
Explanation:
The figure is likely to be similar to the one attached. Writing the equation for forces we have
F-T=Fa/g where F is the force, T is tension, a is acceleration and g is acceleration due to gravity. Substituting the figures we have the first equation as
30 N - T = (30/9.81)a
Also, we know that T=F*a/g and substituting 10N for F we obtain the second equation as
T = (10/9.81)a
Adding the first and second equations we obtain
30 = 4.077471967
a Hence

and T=a hence
T is approximately 7.4 N
Answer:
D.
Explanation:
But this just happen for big stars, like more than 20x the Sun mass.
Shortly: A nebula is a cloud of gas and dust, the material starts to be acummuleted and became a protostar (is like a big planet, almost a star). With enought mass this is a star, burn hydrogen and transform it in Helium.
This occurs in Main Sequence, is about almost all the life time of a star. Then starts the lack of hydrogen. Gravity compress everything, pressure goes up and heat all. Too much energy, Helium get burned and the star grews fast, became a Red Giant. Time pass and the fuel is over, no more making fusion, gravity compress the star, too much strenght, colapses, neutron star.
If it have pretty mass, ok. If have more than like 2x Sun mass, became a blackhole.
Answer:
98 m √
Explanation:
How about s = Vo * t + ½at² ?
s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6
and
h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490
Subtract 2nd from first:
0 = -8Vo + 470.4
Vo = 58.8 m/s
h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m