The youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
<h3 /><h3>What is electric power?</h3>
It is the rate of the electric work done. Its unit is the watt. Horsepower is the unit of power.
A person under the age of 12 may only legally operate a boat with a motor that has more than 6 horsepower but no more than 35 horsepower
if they meet two requirements: they have a boating safety certificate, which they must have on board; and they are being closely watched by an adult who is at least 16 years old.
Hence the youngest age that this person can be and legally operate a boat powered by a motor of more than 35 hp will be 12 years of age.
To learn more about electric power refer to the link;
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Answer:
time is 5.973826 sec
Explanation:
Given data
diameter D = 6.0 mm 6×
m
separated d = 0.010 m
distance (dis) 185 m
speed s = 16 m/s
wavelength = 550 nm = 550
m
to find out
How much time passes
solution
we know that for resolution we use Rayleigh's Criterion i.e
θ = 1.22 wavelength / diameter = separated / distance 1
we calculate distance 1 by put value wavelength, diameter and separated
distance 1 = diameter × separated / 1.22 wavelength
distance 1 = 6×
× 0.010 / 1.22 × 550 × 
distance 1 = 89.418778
so time will be i.e = distance (dis) - distance 1 / speed
time = ( 185 - 89.418778) / 16
time = 5.973826 sec
time is 5.973826 sec
Answer: 6.67 m/s
Explanation:
Recall that average speed is the total distance covered by a moving body divided by the total time taken. The SI unit is metres per second.
i.e Average speed = distance/time taken
Given that:
Distance covered = 6.00 km
Convert kilometers to meters
If 1 km = 1000 m
6.00 km = (6.00 x 1000) = 6000m
Time taken to school = 0.250 hours
Convert time in hours to seconds
If 1 hour = 60 minutes & 1 minute = 60 seconds
Then, 0.250 hours = (0.250 x 60 x 60)
= 900 seconds
Average speed = ?
Average speed = 6000m/900s
= 6.67 m/s
Thus, your average speed to school is 6.67 m/s
The wavelength will remain unchanged.
Explanation:
The velocity
of a wave in terms of its wavelength
and frequency
is
(1)
so if we double both the velocity and the frequency, the equation above becomes
(2)
Solving for the wavelength from Eqn(2), we get

We would have gotten the same result had we used Eqn(1) instead.