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pantera1 [17]
3 years ago
6

A crane drops a 0.25kg steel ball onto a steel plate. The ball's speeds just before impact and after are 5.0m/s and 4.7m/s, resp

ectively. If the ball is in contact with the plate for 0.035s, what is the magnitude of the average force that the ball exerts on the plate during impact?
Physics
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

2.14N

Explanation:

According to Newtons second law

F = ma

F = m(v-u)/t

m = 0.25kg

v= 5.0m/s

u = 4.7m/s

t = 0.035s

Substitute

F = 0.25(5-4.7)/0.035

F = 0.25(0.3)/0035

F = 0.075/0.035

F = 2.14N

Hence the required force is 2.14N

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