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3 years ago

WILL MARK BRAINLIEST!!!! BRAINLIEST! Write 206 in base 7

Mathematics

2 answers:

jekas [21]3 years ago

7 0

Answer:

idfk :)

Step-by-step explanation:

Sonja [21]3 years ago

5 0

10212 is the answer for sure

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Professor Tangent was stumped. His research assistant had given him a riddle but she simply could not solve. Help the professor!

melomori [17]

Answer:

difficult but easy do it yourself you can do you can do you can do bro ...

8 0

3 years ago

A) Find a polynomial, which, when added to the polynomial 5x2–3x–9, is equivalent to: 18

VMariaS [17]

Answer:

a) $-5x^{2}+3x+27$

b) $-5x^{2}+3x+9$

Step-by-step explanation:

a) Let the required polynomial be p(x).

We have the relation, $5x^{2}-3x-9$ + p(x) = 18

i.e. p(x) = 18 $-5x^{2}+3x+9$

i.e. p(x) = $-5x^{2}+3x+27$

b) Let the required polynomial be q(x).

We have the relation, $5x^{2}-3x-9$ + q(x) = 0

i.e. q(x) = 0 $-5x^{2}+3x+9$

i.e. q(x) = $-5x^{2}+3x+9$

3 0

3 years ago

Read 2 more answers

A carpenter goes through 3.4 boxes of nails

jeka57 [31]

4.5 boxes of nails are required for finishing 2 tables

Step-by-step explanation:

Given:

3.4 boxes of nails are required for finishing 1.5 tables

Required:

How much boxes of nails would he use for finishing 2 tables

Solution:

We can solve using Unitary Method:

Nails needed to finish 1.5 tables = 3.4 boxes

Nails needed to finish 1 table = $\frac{3.4}{1.5}\,\,boxes$

Nails needed to finish 2 tables = $\frac{3.4}{1.5}*2 =4.5\,\,boxes$

So, 4.5 boxes of nails are required for finishing 2 tables.

Keywords: Word Problems

Learn more about Word Problems at:

#learnwithBrainly

4 0

3 years ago

S_A_V [24]

Answer:

tje gorilla weights 240 lb

6 0

2 years ago

Read 2 more answers

How to do this question plz answer me

Sati [7]

Answer:

$d = \frac{4 - 3c}{c + 1}$

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

$c = \frac{4 - d}{d + 3}$

Remove the fraction by multiplying (d +3) on both sides:

$c(d + 3) = 4 - d$

Expand:

$cd + 3c = 4 - d$

Bring all the d terms to one side and move the others to the other side of the equation:

$cd + d = 4 - 3c$

Factorise d out:

$d(c + 1) = 4 - 3c$

Divide by (c +1) on both sides:

$d = \frac{4 - 3c}{c + 1}$

7 0

3 years ago