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olchik [2.2K]
3 years ago
13

On a test Juan got 85% or 119 of the items correct. How many items were on the test

Mathematics
2 answers:
Arada [10]3 years ago
6 0

Base = (Percentage/Rate)

B = 119/0.85 = 140

There were 140 items on the test.

Natali [406]3 years ago
4 0
85%=119
119 divides by 0.85= 140

(Double check) 140 times 85= 119

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Answer:b

Step-by-step explanation:

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a rectangle plot measure 20ft. by 30ft. A 3-ft.-wide sidewalk surrounds it.Find the area of the sidewalk.
goldenfox [79]
Area of a rectangle = length (l) * width (w)
A = 30ft * 20ft
A = 600 sq ft

Now the width of a sidewalk that surroundeds it = 3 ft
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Which transformations of ƒ(x) = 3x does h(x) = -3x - 7 represent? reflection over the y-axis and shifted 7 units down reflection
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reflection over the x-axis and shifted 7 units down

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Is y=7x-3 have a proportional relationship
Black_prince [1.1K]

Answer:

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Step-by-step explanation:

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3 years ago
I’m stuck can some one help me
abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-7, x_2=-10,y_2=8

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-10, x_2=3,y_2=10

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

x^2-3x-28

We will break the middle term and find factors

x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

x^2+6x+8

We will break the middle term and find factors

x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)

So, the factors are (x+4)(x+2)

Option A is correct.

7 0
2 years ago
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