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Fed [463]
3 years ago
7

Allyson Felix ran the fastest time of the year for the women's 400 meter dash.

Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

50 seconds

Step-by-step explanation:

If you look at some of her videos, you can see that she runs about a 50 second 400 meter dash.

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You can paint 75 square feet of a surface every 45 minutes. Determine how long it takes you to paint a wall with the given dimen
Allisa [31]

Answer:

25.2 min

Step-by-step explanation:

3 0
3 years ago
Solve both equations and pls show work.. <br> I will mark brainliest
Alexxx [7]

Answer:

7. x = 4

8. x = 10

Step-by-step explanation:

7. The angles are equal to each other so you can do

40 = 12x - 8

48 = 12x

4 = x

8. The angles add up to be 180 degrees so you can combine them and set them equal to 180

6x + 12x = 180

18x = 180

x = 10

8 0
3 years ago
How do i solve that question?
yawa3891 [41]

a) The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }.

b) The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}.

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}.

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable (y, t) in each side of the identity:

6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t (1)

6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C

Where C is the integration constant.

By table of integrals we find the solution for each integral:

-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C

If we know that x = 0 and y = 1<em>, </em>then the integration constant is C = -2.

The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }. \blacksquare

b) In this case we need to solve a first order ordinary differential equation of the following form:

\frac{dy}{dx} + p(x) \cdot y = q(x) (2)

Where:

  • p(x) - Integrating factor
  • q(x) - Particular function

Hence, the ordinary differential equation is equivalent to this form:

\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x} (3)

The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}. \blacksquare

The solution for (2) is presented below:

y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C (4)

Where C is the integration constant.

If we know that p(x) = -\frac{1}{x} and q(x) = x^{2} + \frac{1}{x}, then the solution of the ordinary differential equation is:

y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C

y = x\int {x} \, dx + x\int\, dx + C

y = \frac{x^{3}}{2}+x^{2}+C

If we know that x = 1 and y = -1, then the particular solution is:

y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}. \blacksquare

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0
3 years ago
Which graph shows a set of ordered pairs that represents a function?
bonufazy [111]

There is a rule for functions:

One input(x-value) can only have one output(y-value).

If one input has more than one output, it is not a function.

(This doesn't apply to outputs, one output can have more than one input and still be a function)

This graph shows a set of ordered pairs that does NOT represent a function because there are two points on x = -3. The input -3 has more than one output of -4 and 4, so it is not a function.

4 0
3 years ago
Y = 2x + 9 + x<br>is this equation linear or nonlinear?​
Volgvan

Answer:

Linear

Step-by-step explanation:

Add  2 x  and  x . y = 3 x + 9  A linear equation is an equation of a straight line, which means that the degree of a linear equation must be  0  or  1  for each of its variables. In this case, the degree of variable  y  is  1  and the degree of variable  x  is  1 .

4 0
3 years ago
Read 2 more answers
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