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3 years ago

1. How much magnesium oxide is produced if 12.1 g of magnesium reacts with 16 g of oxygen

Chemistry

1 answer:

melamori03 [73]3 years ago

8 0

Answer:

20.2g (3 s.f.)

Explanation:

Please see attached picture for full solution.

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Balance CH4+O2->CO2+H2O

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What are the 2 basic parts of an atom?

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Answer:

nucleus and electrons

Explanation:

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If the temperature of an object is 335K,how would his be expressed on the celsius scale ?

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At STP how many molecules of nitrogen gas are in 224 L?

NeTakaya

Answer:

6.022×10²² molecules

Explanation:

Given data:

Volume of nitrogen = 224 L

Pressure = standard = 1 atm

Temperature = standard = 273 K

Number of molecules = ?

Solution:

PV = nRT

1 atm × 224 L = n × 0.0821 atm.L/mol.K × 273 K

224 atm.L = n ×22.41 atm.L/mol

n = 224 atm.L/22.41 atm.L/mol

n = 10 mol

1 mole contain 6.022×10²³ molecules

10 mol×6.022×10²³ molecules/ 1 mol

60.22×10²³ molecules

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6 0

2 years ago

A chemical reaction that is expected to form 325.0 gof product only forms 123.8 g of product. What is the percent yield of this

Tasya [4]

Answer:

$\boxed {\boxed {\sf A. \ 38.1 \%}}$

Explanation:

Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:

$\% \ yield = \frac{actual \ yield}{theoretical \ yield} *100$

For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.

$\% \ yield = \frac{ 123.8 \ g }{325.0 \ g }*100$

Divide.

$\% \ yield = 0.380923077 *100$

$\% \ yield = 38.0923077$

Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .

$\% \ yield \approx 38.1$

The percent yield is about <u>38.1%</u>

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