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Otrada [13]
3 years ago
5

The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ________.

Chemistry
2 answers:
Maru [420]3 years ago
7 0

Explanation:

A nuclear reaction is defined as a reaction in which two nuclei combine together to result in the formation of a new nuclei.

When two nuclei combine together then it is known as nuclear fusion. And, when a large nuclei split into two small nuclei then it is known as a nuclear fission reaction.

For example, ^{31}P + ^{1}_{0}n \rightarrow ^{27}_{13}Al + ^{4}_{2}He + ^{1}_{0}e

As we know that alpha particle is ^{4}_{2}He.

So, when ^{31}P is subjected to neutron capture followed by alpha emission then products are ^{27}_{13}Al along with emission of a positron.

faltersainse [42]3 years ago
6 0
The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ²⁸Al.
Nuclear reaction: ³¹P + n° → ²⁸Al + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.</span>
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Answer:

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Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Answer

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Explanation:

Cr2O7^2-(aq) + Hg(l) ----> Hg^2+(aqH) + Cr^3+(aq)

add H^1+ (acid) to capture the O and make 7 water molecules

Cr2O7^2-(aq) + Hg(l) + H^1+ ----> Hg^2+(aqH) + Cr^3+(aq) + 7H2O

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so

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

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the equation is balanced

we cannot balance the equation in a basic solution with OH^1-

we have plenty of O in the dichromate ion. we need to convert it to water which take free H^1+ from the acid

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