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Otrada [13]
3 years ago
5

The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ________.

Chemistry
2 answers:
Maru [420]3 years ago
7 0

Explanation:

A nuclear reaction is defined as a reaction in which two nuclei combine together to result in the formation of a new nuclei.

When two nuclei combine together then it is known as nuclear fusion. And, when a large nuclei split into two small nuclei then it is known as a nuclear fission reaction.

For example, ^{31}P + ^{1}_{0}n \rightarrow ^{27}_{13}Al + ^{4}_{2}He + ^{1}_{0}e

As we know that alpha particle is ^{4}_{2}He.

So, when ^{31}P is subjected to neutron capture followed by alpha emission then products are ^{27}_{13}Al along with emission of a positron.

faltersainse [42]3 years ago
6 0
The product of the nuclear reaction in which 31p is subjected to neutron capture followed by alpha emission is ²⁸Al.
Nuclear reaction: ³¹P + n° → ²⁸Al + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.</span>
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Is nitride on the periodic table
sasho [114]

Answer:

yes

Explanation:

Nitride, any of a class of chemical compounds in which nitrogen is combined with an element of similar or lower electronegativity, such as boron, silicon, and most metals.

4 0
3 years ago
The atomic number of an element is 71. is this element diamagnetic or paramagnetic?
Mrrafil [7]
The  element  with atomic  number  71(lutetium) is  paramagnetic

  This  is  because  all  its   electrons   is  not  paired .  lutetium  has  electron  configuration  of  (Xe) 4f^14 5d^1 6S^2
Its 5d   sub shell  is  not  paired  since  the  d  sub shell  can  accommodate  a total  of  10   electrons  hence  lutetium  is  paramagnetic
5 0
3 years ago
Read 2 more answers
A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0
miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

Q_{metal} - Q_{water} = 0

Q_{metal} = Q_{water}

Where:

Q_{water} - Heat received by water, measured in joules.

Q_{metal} - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})

The specific heat of the metal is cleared within equation above:

c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}

If we know that m_{water} = 0.237\,kg, m_{metal} = 0.244\,kg, c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}, T_{w,o} = 10\,^{\circ}C, T_{m,o} = 100.10\,^{\circ}C and T = 15.30\,^{\circ}C, the specific heat of molybdenum is:

c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}

c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

5 0
3 years ago
How do scientists represent atoms that are bonded together?​
DaniilM [7]

Answer:

When atoms join together to form molecules, they are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons between the atoms. It is only the electrons in the outermost shell that ever get involved in bonding.

7 0
3 years ago
Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.
mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0
3 years ago
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