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Tju [1.3M]
2 years ago
13

Write the balanced equation for the reaction of acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3). What type of reaction(s)

took place?
Please Provide an Explanation. Thank-you!
Chemistry
2 answers:
stealth61 [152]2 years ago
5 0

Answer:CH3COOH + NaHCO3 > H2O + CO2(g) + CH3COONa

Explanation:acid and base neutralize creating water and CO2 gas along with a salt

Setler [38]2 years ago
5 0

Answer:

1. CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2

2. Double Displacement and Decomposition reaction.

Explanation:

1. The balanced equation for the reaction is given below:

CH3COOH + NaHCO3 —> CH3COONa + H2O + CO2

2. There are actually two types of reactions that occur in the reaction between acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3)

The first is a DOUBLE DISPLACEMENT reaction in which the acetic acid react with the bicarbonate to form sodium acetate and carbonic acid as shown below:

CH3COOH + NaHCO3 —> CH3COONa + H2CO3

The second type of reaction is DECOMPOSITION REACTION. The carbonic acid (H2CO3) form is unstable and will decompose to form H2O and CO2 as shown below:

H2CO3 —> H2O + CO2

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How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g
Serhud [2]

<u>Answer:</u> The energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

<u>Explanation:</u>

First we have to calculate the mass defect (\Delta m).

The equation for the alpha decay of thorium nucleus follows:

_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

\Delta m=(m_{Ra}+m_{He})-(m_{Th})

\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg

(Conversion factor: 1amu=1.66\times 10^{-27}kg )

To calculate the energy released, we use Einstein equation, which is:

E=\Delta mc^2

E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2

E=2.0916\times 10^{-13}J

The energy released for 230 grams of decay of thorium is 2.0916\times 10^{-13}J

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = 2.0916\times 10^{-13}J

Then, 3 grams of Th will release energy of = \frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J

Hence, the energy released for the decay of 3 grams of 230-Thorium is 2.728\times 10^{-15}J

5 0
2 years ago
PLEASE HELP ASAPP!!!!! WILL MARK BRAINLIEST
Aloiza [94]

Answer:

400°C

Explanation:

22,000 cal / (0.11 cal/g°C x 500 g) = 400°C

3 0
2 years ago
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Colt1911 [192]
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3 years ago
In a labratory activity the density of a sample of vanadium is determined to be 6.9g/cm^3 at room temperature. what is the perce
Snowcat [4.5K]

Answer:

c : 13%

Explanation:

Data Give:

Experimental density of vanadium = 6.9 g/cm³

percent error = ?

Solution:

Formula used to calculate % error

  % error = [experimental value -accepted value/accepted value] x 100

The reported accepted density value for vanadium = 6.11 g/cm³

Put value in the above equation

                  % error = [ 6.9 - 6.11 / 6.11 ] x 100

                  % error = [ 0.79 / 6.11 ] x 100

                  % error = [ 0.129] x 100

                  % error = 12.9

Round to the 2 significant figure

% error = 13 %

So, option c is correct            

7 0
3 years ago
Give the four symbols for physical states of reactants and products, and tell what each means.
pshichka [43]
We are going to use table salt, NaCl as an example.

(s) = solid, eg the salt you put on your food is a crystalline solid. 
(l)  = liquid, if you melt salt it take on a liquid form
(g)  = gaseous, if you put enough energy in the salt will turn into a gas.
(aq) = aqueous, meaning in water or another solvent. If you put some table salt in water and stir it, it will dissolve, the NaCl molecules dont get destroyed but they dissolve becoming part of the liquid. 
6 0
2 years ago
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