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2 years ago

(a) Give one function each of the following equipments

Chemistry

1 answer:

igomit [66]2 years ago

4 0

Functions of the following equipment's are-

1. ASPIRATOR is a suction machine .It is a medical device that is primarily used for removing obstructions such as mucus, saliva, blood, or secretions — from a person's airway.

2.Beakes are useful as a reaction container for holding liquid or solid samples. They are also used for catching liquids from titrations and filtrates from filtering operations.

3. pipettes are used in laboratory to measure out or transfer small quantities of liquid, in volumes of milliliters (mL), microliters (μL).

4. fire tongs are used for holding hot apparatus.

5. test tubes are used for holding solutions and carrying out the reactions.

refer brainly.com/question/24690874

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2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'

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Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

$\displaystyle M_1V_1= M_2V_2$

Where M represents molarity and V represents volume.

Let the initial concentration and unknown volume be M₁ and V₁, respectively. Let the final concentration and required volume be M₂ and V₂, respectively. Solve for V₁:

$\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}$

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
$\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}$

Convert this value to mL:
$\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}$

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

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