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Irina18 [472]
2 years ago
14

(a) Give one function each of the following equipments

Chemistry
1 answer:
igomit [66]2 years ago
4 0

Functions of the following equipment's are-

1. ASPIRATOR  is a  suction machine .It is a  medical device that is primarily used for removing obstructions  such as  mucus, saliva, blood, or secretions — from a person's airway.

2.Beakes  are useful as a reaction container for holding  liquid or solid samples. They are also used for catching liquids from titrations and filtrates from filtering operations.

3. pipettes are used in laboratory to measure out or transfer small quantities of liquid, in volumes of milliliters (mL), microliters (μL).

4. fire tongs are used for holding hot apparatus.

5. test tubes are used for holding solutions and carrying out the reactions.

refer brainly.com/question/24690874

#SPJ2

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Climate is the __________________ average weather conditions that occur in a particular region.
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Explanation:

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Removing one electron from an atom results in the formation of an Question 7 options: ion with a 1- charge. ion with a 7+ charge
olga nikolaevna [1]

I believe it is an ion with a 1+ charge. If you remove an electron from an atom it will have a positive charge. But if you add electrons it will be a negative charge. Hope I helped!

5 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
2 years ago
Michelle has a cup of hot coffee. The liquid coffee weighs 236 grams. Michelle adds a few teaspoons sugar and 25 grams of milk t
sineoko [7]

Answer:

10grams

Explanation:

So it weighs 236 grams added with 25 grams. So it now weighs 261 grams so 10 grams of sugar remains in it.

7 0
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