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3 years ago

How many F's can I get in order to still pass 7th grade??? What's the maximum??

2 answers:

6 0

:D i hav th same question cuz i hav lik 3 E's
probably one failing grade each quarter or marking period w.e ur school calls it
ik in my school i cn get honor role even tho i hav one C soooo ^thts wat im thinkin

AlekseyPX3 years ago

4 0

I think you can have about 3 or 4, depends on the district I think, but if you need help with classes, I have all A's. So just msg me for help :)

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What are the greatest common factors of 15 and 6

laiz [17]

The greatest common factor is 3.

7 0

2 years ago

Read 2 more answers

An angle whose measure is –302° is in standard position. In which quadrant does the terminal side of the angle fall?

juin [17]

Answer: Quadrant 1 (northeast quadrant)

=================================================

Explanation:

Add on 360 degrees to do a full rotation

-302+360 = 58

So angles -302 degrees and 58 degrees are pointing in the same direction. These angles are in quadrant 1, which is the northeast quadrant

Note: because the angles -302 and 58 point in the same direction, we consider these angles to be coterminal.

3 0

3 years ago

In ΔVWX, the measure of ∠X=90°, WV = 65, XW = 16, and VX = 63. What ratio represents the tangent of ∠V?

djyliett [7]

Answer:

tanV= adjacent /opposite =

$\frac{16}{63}$

Step-by-step explanation:

4 0

3 years ago

First, Khianna must walk from the front gate to the Ferris wheel. This distance is 2.5 cm on Khianna's map. How far is the actua

spin [16.1K]

Okie doke. 1cm on the map equals 500 meters. The distance from the gate to the ferris wheel on the map is 2.5cm. To find the actual distance, multiply the length on the map by the distance per centimeter. 500 * 2.5 is 1,250. The actual distance is 1,250 meters.

Note: When it comes to problems like these, you must always multiply the distance on the map by the scale unit (in other words, the actual distance on how far it is per the smaller unit).

7 0

2 years ago

I'm have some issues with the problem shown in the screenshot and would love some help.

KiRa [710]

The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;

Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.

Maximum volume of the box is approximately 1048.6 in.³

<h3>How can the dimensions and volume of the box be calculated?</h3>

The given dimensions of the cardboard are;

Width = 18 inches

Length = 35 inches

Let <em>x </em>represent the side lengths of the cut squares, we have;

Width of the box formed = 18 - 2•x

Length of the box = 35 - 2•x

Height of the box = x

Volume, <em>V</em>, of the box is therefore;

V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x

By differentiation, at the extreme locations, we have;

$\frac{d V }{dx} = \frac{d( 4 \cdot \: {x}^{3} - 106 \cdot \: {x}^{2} + 630\cdot \: {x} ) }{dx} = 0$

Which gives;

$\frac{d V }{dx} =12\cdot \: {x}^{2} - 212\cdot \: {x} + 630 = 0$

6•x² - 106•x + 315 = 0

$x = \frac{ - 6 \pm \sqrt{106 ^2 - 4 \times 6 \times 315} }{2 \times 6}$

Therefore;

x ≈ 4.55, or x ≈ -5.55

When x ≈ 4.55, we have;

V = 4•x³ - 106•x² + 630•x

Which gives;

V ≈ 1048.6

When x ≈ -5.55, we have;

V ≈ -7450.8

The dimensions of the box that gives the maximum volume are therefore;

Width ≈ 18 - 2×4.55 in. = 8.89 in.

Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.

Height = x ≈ 4.55 in.

The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³

Learn more about differentiation and integration here:

brainly.com/question/13058734

#SPJ1

7 0

1 year ago