All categories

3 years ago

Eighteen less than three times a number is twice the number. Write and solve

Mathematics

1 answer:

goblinko [34]3 years ago

8 0

Answer:

The number is 18

Step-by-step explanation:

You can write an equation to represent this. Let x represent the unknown number.

3x - 18 = 2x

Move 2x to the left side. Remember, "change the side, change the sign." Add 0 as a placeholder to the right of the equals sign.

3x - 2x - 18 = 0

Simplify like terms.

x - 18 = 0

Move -18 to the right of the equals sign.

x = 18

Now that we know x = 18, we can substitute it into the problem.

"Eighteen less than three times 18 is two times 18."

18 x 3 = 54

54 - 18 = 36

36 is, in fact, two times 18. We can check this by dividing 36 by 2.

36 ÷ 2 = 18

You might be interested in

Let f(x)=3x+5 and g(x)=x^2.

Nady [450]

Answer: x² + 3x + 5

<u>Step-by-step explanation:</u>

f(x) = 3x + 5 g(x) = x²

(f + g)(x) = f(x) + g(x)

= 3x + 5 + x²

= x² + 3x + 5

3 0

3 years ago

Which situation could be represented by linear function

ddd [48]

Answer:

d. The amount of people in a town increase by 50 people every 5 years.

Step-by-step explanation:

this is because if you were to graph it, it would be a straight line while the other options the line would be curved.

8 0

3 years ago

3.3^(2x+1)-103^x+1=0 need value of x

photoshop1234 [79]

Answer:

The value of $x$ is approximately -1.531.

Step-by-step explanation:

Let $3.3^{2\cdot x + 1}-103^{x+1} = 0$ , we proceed to solve this expression by algebraic means:

1) $3.3^{2\cdot x + 1}-103^{x+1} = 0$ Given

2) $3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0$ $a^{b}\cdot a^{c} = a^{b+c}$

3) $(3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$

4) $(3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0$ $(a^{b})^{c} = a^{b\cdot c}$ /Commutative property

5) $\left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0$ Existence of multiplicative inverse/Definition of division/Modulative property/ $a^{b}\cdot a^{c} = a^{b+c}$

6) $\left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3}$ Existence of additive inverse/Modulative property/ $(a^{b})^{c} = a^{b\cdot c}$

7) $\log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3}$ Definition of logarithm.

8) $2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}$ $\log_{b} a^{c} = c\cdot \log_{b} a$

9) $2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3$ $\log_{b} \frac{a}{d}$

10) $x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3$ $\log_{b} a^{c} = c\cdot \log_{b} a$ /Associative property

11) $x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}$ Existence of multiplicative inverse/Definition of division/Modulative property

12) $x \approx -1.531$ Result

The value of $x$ is approximately -1.531.

4 0

3 years ago

Can i get some help?

poizon [28]

Answer:

The second one (4+3x = 9)

Step-by-step explanation:

From the working we can already tell that the second one is the odd one out without even doing the 4th one

6 0

3 years ago

Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What

Kitty [74]

We are given : Cost of a gallon of milk = $2.50.

Cost of a cup of yogurt = $1.20.

Total money Monica has = $20.

Number of cups of yogurt Monica can buy = x.

And inequality made is also correct

1.20x + 2.5 ≤ 20.

Now, we need to solve it for x.

Subtracting 2.5 from both sides, we get

1.20x + 2.5 -2.5 ≤ 20 - 2.5.

1.20x ≤ 17.5

Dividing both sides by 1.20, we get

1.20x/1.20 ≤ 17.5/1.20.

x ≤ 14.5833...

Because it's less than 15, so final answer is : 14 is greatest number of cups of yogurt Monica can buy.

3 0

3 years ago

Read 2 more answers