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umka2103 [35]
2 years ago
8

The ________ is located inside the outdoor condenser unit and receives the low-pressure refrigerant vapor through the suction li

ne and squeezes it into a smaller volume at a higher pressure.
Physics
1 answer:
dusya [7]2 years ago
6 0

Answer:

Compressor

Explanation:

Compressor - the compressor is a unit that placed at the inner side of the condenser. The main function of the compressor is to increase the pressure by reducing the volume of air. And this reduced volume of air is compressed for the cleaning purpose of the air tube. While condenser is used for heat exchange which converts steam into liquid form.  

It is advisable not to operate the compressor when the outside temperature is below 65 degrees F.

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The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. In this problem you can appro
Pavel [41]

Answer:

A)A=12.2480\ m^2

B)12.2480\pm 0.1029\ m^2

Explanation:

<u>Given:</u>

Length of the room l= 3.92 ± 0.0035

Width of the room w= 3.15 ± 0.0055

A) Let A be the area of the room

A=l\times w\\A=3.92\times3.15\\A=12.2480\ \rm m^2

B)We will calculate uncertainty in each dimension

%uncertainty in length=\dfrac{0.0035}{3.92}\times 100=0.0892\ %

%uncertainty in width =\dfrac{0.0055}{3.15}\times 100=0.0174%

The uncertainty in area will be sum of uncertainty in length and width

%uncertainty in Area=  %uncertainty in length + %uncertainty in width

%uncertainty in Area=0.0892\ % + 0.0174\ %

%uncertainty in Area=0.0106

Uncertainty in Area=0.0106\times 12.2480=0.1029\ \rm m^2

There Area is12.2480 ± 0.1029\ \rm m^2

7 0
2 years ago
A 285-mL flask contains pure helium at a pressure of 750 torr . A second flask with a volume of 455 mL contains pure argon at a
zaharov [31]

Answer:

P_{He}^|=288.85torr

Explanation:

Given data

P_{He}=750 torr\\V_{He}=285mL\\P_{Ar}=732 torr\\V_{Ar}=455 mL

Required

Partial pressure of helium

Solution

First calculate the total volume of gas mixture once the stopcock is opened

So

V_{total}=V_{He}+V_{Ar}\\V_{total}=285mL+455mL\\V_{total}=740mL

As temperature remains constant,by Boyle's Law we calculate the partial pressure of the helium gas

So

P_{He}V_{He}=P_{He}^|V_{total}\\P_{He}^|=\frac{P_{He}V_{He}}{V_{total}}\\P_{He}^|=\frac{750torr*285mL}{740mL}\\  P_{He}^|=288.85torr

5 0
3 years ago
Read 2 more answers
Sir William Herschel counted the number of stars in different directions, and getting similar numbers in each direction along th
AVprozaik [17]

Answer: the correct answer is (B) He did not know that interstellar dust made it hard from him to see a large part of the Milky Way's disk.

Explanation:

We live in a dusty Galaxy. Because interstellar dust absorbs the light from stars, Herschel could see only those stars within about 6000 light-years of the Sun.

8 0
2 years ago
Find the length of an arc with a radius of 6.0m swept across 2.5 radians.
soldier1979 [14.2K]

Hello!

In terms of an arc length, radians is the measurement of an arc length in terms of the original radius. This arc length is 2.5 radians, so we multiply it by our original radius.

2.5(6)=15

Therefore, the arc length is 15 meters.

I hope this helps!


7 0
3 years ago
A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
Crank

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

8 0
2 years ago
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