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3 years ago

Calculate the momentum of a 953kg elephant running at a rate of 3.85 m/s.

1 answer:

6 0

Hi!
So we got 953kg = mass
And we also got 3.85 = speed
M/S = 953/3.85
953/3.85= 247.532468
ANSWER: 247.532468
Hope I helped! :D

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Which value is most likely to be the pH of a salt that is formed by the reaction of a strong acid and a weak base?

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In a hydrolysis reaction between a strong acid and a weak base, the salt formed will have a pH less than 7. By virtue of this phenomenon between weak bases and strong acids, the anion of the strong acid will fail to attract the hydrogen ion, while the cation from the weak base will donate a proton to the water forming a hydronium ion.

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2 years ago

What single property was the most important in Jesseca’s material?

aleksandrvk [35]

Answer:

Jesseca wanted to create a material that reflected most of the light that fell on it.

Explanation:

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2 years ago

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A ball is dropped from rest. how fast is the ball going after 3 seconds

Airida [17]

Answer:

v = 29.4m/s

Explanation:

Since the ball is dropped at rest,

u = 0m/s

a = 9.81m/s²

Using

v = u + at

After 3 seconds,

v = 0 + (9.81)(3)

v = 29.4m/s

5 0

3 years ago

Rank these temperatures from hottest to coldest: 32° F,32° C, and 32 K 320 F> 32° C>32 K 32°C 32° F 32 K 32° F 32 K 32° c

Leviafan [203]

Answer:

32 C > 32 F > 32 K

Explanation:

32 F, 32 C, 32 K

Let T1 = 32 F

T2 = 32 C

T3 = 32 K

Convert all the temperatures in degree C

The relation between F and C is given by

(F - 32) / 9 = C / 100

so, (32 - 32) / 9 = C / 100

C = 0

So, T1 = 32 F = 0 C

The relation between c and K is given by

C = K - 273 = 32 - 273 = - 241

So, T3 = 32 K = - 241 C

So, T 1 = 0 C, T2 = 32 c, T3 = - 241 C

Thus, T2 > T1 > T3

32C > 32 F > 32 K

3 0

3 years ago

On the way home from school, Taylor's car runs out of gas. He has to walk 25m north and 10m west in order to reach the nearest g

spin [16.1K]

Answer:

The distance is 35 m and the magnitude of the displacement is 26.93 m

Explanation:

Displacement and Distance

These are two related concepts. A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is calculated independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the object. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.

Taylor walks 25 m north and 10 m west. The total distance is the sum of both numbers:

d = 25 m + 10 m = 35 m

To calculate the displacement, we need to know the final position with respect to the initial position. If we set the coordinates of Taylor's car as the origin (0,0), then his final position is (-10,25), assuming the west direction is negative and the north direction is positive.

The magnitude of the displacement is the distance from (0,0) to (-10,25):

$D=\sqrt{(25-0)^2+(-10-0)^2}$

$D=\sqrt{625+100}=\sqrt{725}$

D = 26.93 m

The distance is 35 m and the magnitude of the displacement is 26.93 m

8 0

3 years ago