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galina1969 [7]
3 years ago
13

You have covered a grounded metal surface with a layer of photoconductor. Working in the dark, you sprinkle negative charge onto

this surface. If you now expose only the left half of the photoconductor to light, you will find that
(A) the left half becomes neutral while the right half remains negatively charged.
(B) nothing happens because there is no changing magnetic field.
(C) negative charge flows from the right side of the photoconductor to the left and both sides become neutral.
(D) the right half becomes neutral while the left half remains negatively charged.
Physics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

A. the left half becomes neutral while the right half remains negatively charged

Explanation:

This is because wherever light strikes the photoconductor, it transforms from an insulator into a conductor. The charge will then migrate through it and leaves its surface. By exposing the left half of the photoconductor to light, you allow its local charge to leave and it becomes neutral.

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a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien
Law Incorporation [45]

Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

Explanation:

Using the definition of the centripetal force we have:

\Sigma F=ma_{c}=m\frac{v^{2}}{R}

Where:

  • m is the mass of the car
  • v is the speed
  • R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

F_{f}=m\frac{v^{2}}{R}

F_{f}=2100\frac{18^{2}}{83}

F_{f}=8197.60 \: N

<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

7 0
3 years ago
A circuit has an overall resistance of 40 ohms and a current of 200mA.
svetoff [14.1K]

Answer:

Hey!

_________________

Voltage (V) = 0.8V

Current (I) = 200 mA = 200/10^3 = 2/10

Resistance = ?

Resistance = Voltage / Current

Voltage = Current × Resistance

0.8 = 2/10 × Resistance

0.8×10/2 = Resistance

8/2 = Resistance

Resistance = 4 ohm

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Hope it helps...!!!

Explanation:

3 0
2 years ago
2. Do you think the density of the ice affected the melting rate of the ice, or do you think adding the objects affected the mel
Setler [38]

The density of ice does not affect its melting rate. Adding objects will affect the melting rate.

  • A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.
  • The term "density" refers to an extensive quality, which means that it is independent of the substance's concentration. Every substance in the world demonstrates its distinctive density. Since it does not fluctuate, it would not affect the rate of melting. The addition of the objects could speed up the process, though, as each one generates heat that could act as the mediating force for the melting process.

To learn more about density, visit :

brainly.com/question/15164682

#SPJ9

3 0
1 year ago
3. Ecology
Korvikt [17]

Answer:

The family would not have hot water unless they were to heat the the water. They would have to depend on the stove in order to survive by heating the house to say alive and not freeze. They would also have to depend on the stove to get hot water to do any, but if the sun goes away for too long and everything starts to die then they will have to use what food and wood that they have in order to survive.

Explanation:

6 0
3 years ago
When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amp
Paraphin [41]

Answer:

796.18 Hz

Explanation:

Applying,

Maximum velocity = Amplitude×Angular velocity

Therefore,

V' = A(2πf)............... Equation 1

Where V' = maximum velocity of the eardrum, A = Amplitude of vibration of the eardrum, f = frequency of the eardrum vibration, π = pie

make f the subject of the equation

f = V'/2πA................ Equation 2

From the question,

Given: V' = 3.6×10⁻³ m/s, A' = 7.2×10⁻⁷ m,

Constant: 3.14.

Substitute these values into equation 2

f = 3.6×10⁻³/( 7.2×10⁻⁷×2×3.14)

f = 796.18 Hz

6 0
3 years ago
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