3 years ago

An 8.38 gram sample of water lost 870 J of heat. What is the change in temperature

1 answer:

6 0

Answer:

Find the mass of a sample of water if its temperature dropped 24.8 degrees Celsius when it lost 870 J of. heat. (specific heat of water is 4.18 J/g x degrees Celsius) 8.38 grams. How many degrees would the temperature of a 450 g piece of iron increase if 7600 J of.

Explanation:

You might be interested in

An object with a mass of 20 kg has a net force of 80 N acting on it. What is the acceleration of the object?

Archy [21]

Answer:

4m/s^2

Explanation:

mass(m)=20 kg

force=80 N

acceleration (a)=?

Therefore,

Force = mass * acceleration

80 = 20*a

a=80/20

=4m/s^2

7 0

1 year ago

What are some of the difficulties with measuring the volume of a gas? Select all that apply.

forsale [732]

Answer:

it is ---D because you can't measure gas and it's mass

HOPE THIS HELPS

6 0

3 years ago

If a car was cruising down the highway at 80 km/hr, how fast would the people inside the car be traveling?

wolverine [178]

Because the people in the car are attached to the vehicle, the people inside the vehicle are going the same speed as the vehicle.

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

An automobile engine delivers 47.4 hp. how much time will it take for the engine to do 6.82 × 105 j of work? one horsepower is e

kogti [31]

1 horsepower is equal to 746 W, so the power of the engine is
$P=47.4 hp \cdot 746 \frac{W}{hp}=35360 W$
The power is also defined as the energy E per unit of time t:
$P= \frac{E}{t}$
Where the energy corresponds to the work done by the engine, which is $E=6.82 \cdot 10^5 J$ . Re-arranging the formula, we can calculate the time t needed to do this amount of work:
$t = \frac{E}{P}= \frac{6.82 \cdot 10^5 J}{35360 W}=19.3 s$

8 0

3 years ago

A tiger runs at 58 km/h [S]. What is the displacement of the tiger in 38 s?

Artyom0805 [142]

58 K/h = 58000/3600= 16.1 m/s
In 38 s displacement is 38x16.1= 612.2 m

3 0

3 years ago