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Kamila [148]
3 years ago
13

A class contributed $8.40 in dimes and quarters to the Red Cross. In all, there were 45 coins. How many coins of each kind were

there?
Mathematics
1 answer:
vfiekz [6]3 years ago
6 0
Let d = # of dimes
Let q = # of quarters
45 = d + q
.1d + .25q = 8.40
Then we can use the substitution method and make it so that d = 45 - q.
Then plug in the value for d into the second equation.
.1(45-q)+.25(q)=8.40
4.5-.1q+.25q=8.40
4.5+.15q = 8.40
.15q = 3.90
q = 26
d = 45 - 26 = 19
26 quarters
19 dimes
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