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stiv31 [10]
3 years ago
9

use the five step plan to solve the word problem. Show all five steps in youre response. doug is twice anns age. doug is 34 year

s old. how old is ann?
Mathematics
1 answer:
vovangra [49]3 years ago
3 0
The answer is anne is 17. You would need to right the correct equation 34=2x. X is anne's age. Then you would divide both sides by 2 (really just divide 34 by 2). 34/2=17.
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Six men completed a task in 24 hrs and 48 min. How long, in hours and minutes, would it take four men to complete the same task?
igor_vitrenko [27]

Answer:

It would take 4 men 37 hrs and 12 mins to complete the same task.

step-by-step explanation:

Let X be the time the four men would use to complete the task.

From the question, 6 men completed a task in 24 hrs and 48 mins

But

24 \: hrs \: 48 \: mins = 24(60mins) + 48 \: mins=1488 \: mins

Using ratio and proportion

6 \: men:1488 \: mins

4  men:x\:mins

if more, less divides and if less, more divides.

4 men required more time to complete the task

Hence:

x =  \frac{6}{4} \times 1488 \: mins

x = 2232 \: mins

x = 37 hrs 12 mins

5 0
3 years ago
Using Postulates and/or Theorems, determine whether ABC~AXY.
Xelga [282]

Answer:

They are not similar

Step-by-step explanation:

To see whether the triangles are similar or not we can compare their side lengths:

AB = 24

AX = 6

AX/AB = 1/4 is the ratio now let's compare this to AY/AC

AY/AC = 10/25 if we simplify this the result will be 2/5 as we can see the side lengths are not proportional so the triangles are not similar.

4 0
3 years ago
Can there be more than one mean or mode in a math problem??
astraxan [27]

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3 years ago
33. Suppose that the scores on a statewide standardized test are normally distributed with a mean of 78 and a standard deviation
tino4ka555 [31]

Given the scores on a statewide standardized test are normally distributed

Mean = μ = 78

Standard deviation = σ = 3

Normalize the data using the z-score by using the following formula and chart:

z=\frac{x-\mu}{\sigma}

Estimate the percentage of scores of the following cases:

(a) between 75 and 81

so, the z-score for the given numbers will be:

\begin{gathered} 75\rightarrow z=\frac{75-78}{3}=\frac{-3}{3}=-1 \\ 81\rightarrow z=\frac{81-78}{3}=\frac{3}{3}=1 \end{gathered}

As shown, the percentage when (-1 < z < 1) = 68%

(b) above 87

87\rightarrow z=\frac{87-78}{3}=\frac{9}{3}=3

The percentage when (z > 3) = 0.5%

(c) below 72

72\rightarrow z=\frac{72-78}{3}=\frac{-6}{3}=-2

The percentage when (z < -2) = 0.5 + 2 = 2.5%

(d) between 75 and 84

\begin{gathered} 75\rightarrow z=\frac{75-78}{3}=-\frac{3}{3}=-1 \\ 84\rightarrow z=\frac{84-78}{3}=\frac{6}{3}=2 \end{gathered}

The percentage when ( -1 < z < 2 ) = 68 + 13.5 = 81.5%

3 0
1 year ago
On a twelve hours clock the time is quarter -past nine. where does the long head and point ?​
AleksAgata [21]

Answer:

It points to 3 in on the clock.

Hope it helps!!!

8 0
3 years ago
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