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levacccp [35]
2 years ago
6

The diagram is being used to illustrate the second law of thermodynamics, where Qh represents a hot object and Qc represents a c

old object.
A black box on the left labeled Q Subscript h Baseline and a touching white box on the right labeled Q Subscript c Baseline.

Which will best complete the diagram to illustrate the law?

adding in the boxes an arrow that points from Qh to Qc
adding in the boxes an arrow that points from Qc to Qh
adding in the boxes an arrow that points in both directions between Qh and Qc
adding in each box an arrow that points upward from Qh and from Qc

The correct answer is A. adding in the boxes an arrow that points from Qh to Qc
Physics
2 answers:
sdas [7]2 years ago
9 0

Answer:

Adding in the boxes an arrow that points from Q_{h} to Q_{c}.

Explanation:

According to the Second Law of Thermodynamics,<em> the heat transfer occur from a higher temperature body to a lower temperature body</em>.

So, applying the Second Law of Thermodynamics, the correct answer is the first one: Adding in the boxes an arrow that points from Q_{h} to Q_{c}; because this direction is pointing the right one, it doesn't violate the second law of the thermodynamics, the heat is gonna go from Q_{h} to Q_{c}, and the arrow indicates that.

Remember that the problem states that Q_{c} is a cold object and Q_{h} is a hot object.

katrin [286]2 years ago
6 0

Answer:

The answer is A. on edgen.

Explanation:

A. adding in the boxes an arrow that points from Qh to Qc

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The AMA is calculated as:
AMA = force obtained / force applied
AMA = 400 / 40
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3 years ago
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A radioactive material has a count rate of 400 per minute. It has a half life of 40 years. How long will it take to decay to a r
cestrela7 [59]

Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

Half-life (t½) = 40 years

Final count rate (Cբ) = 25 count/min

Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

Number of half-lives (n) =?

Cբ = 1/2ⁿ × Cᵢ

25 = 1/2ⁿ × 400

Cross multiply

25 × 2ⁿ = 400

Divide both side by 25

2ⁿ = 400/25

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:

Half-life (t½) = 40 years

Number of half-lives (n) = 4

Time (t) =?

n = t / t½

4 = t / 40

Cross multiply

t = 4 × 40

t = 160 years.

Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.

7 0
2 years ago
Sue and jenny kick a soccer ball at exactly the same time. sue's foot exerts a force of 57.6 n to the north. jenny's foot exerts
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A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of
umka21 [38]

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

(a)If line is moving up with constant velocity i.e. there is no acceleration

This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

Maximum weight in this case will be 50 N

(b)acceleration of magnitude 2.98 m/s^2

T-mg=ma

50=m\left ( g+a\right )

50=m\left ( 12.78\right )

m=3.91

Therefore weight is 3.91\times 9.8=38.34 N

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