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levacccp [35]
2 years ago
6

The diagram is being used to illustrate the second law of thermodynamics, where Qh represents a hot object and Qc represents a c

old object.
A black box on the left labeled Q Subscript h Baseline and a touching white box on the right labeled Q Subscript c Baseline.

Which will best complete the diagram to illustrate the law?

adding in the boxes an arrow that points from Qh to Qc
adding in the boxes an arrow that points from Qc to Qh
adding in the boxes an arrow that points in both directions between Qh and Qc
adding in each box an arrow that points upward from Qh and from Qc

The correct answer is A. adding in the boxes an arrow that points from Qh to Qc
Physics
2 answers:
sdas [7]2 years ago
9 0

Answer:

Adding in the boxes an arrow that points from Q_{h} to Q_{c}.

Explanation:

According to the Second Law of Thermodynamics,<em> the heat transfer occur from a higher temperature body to a lower temperature body</em>.

So, applying the Second Law of Thermodynamics, the correct answer is the first one: Adding in the boxes an arrow that points from Q_{h} to Q_{c}; because this direction is pointing the right one, it doesn't violate the second law of the thermodynamics, the heat is gonna go from Q_{h} to Q_{c}, and the arrow indicates that.

Remember that the problem states that Q_{c} is a cold object and Q_{h} is a hot object.

katrin [286]2 years ago
6 0

Answer:

The answer is A. on edgen.

Explanation:

A. adding in the boxes an arrow that points from Qh to Qc

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3 years ago
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3 years ago
An inductor in an LC circuit has a maximum current of 2.4 A and a maximum energy of 56 mJ.
Harrizon [31]

Answer:

The energy stored in the capacitor, when the current in the inductor is 1.2 A, is 41.6 mJ.

Explanation:

In a LC oscillating circuit, the energy is stored in the electric field (between the plates of the capacitor) and in the magnetic field (surrounding the wires of the inductor).

At any time, the sum of both energies can be expressed as follows:

E = 1/2 Q² / C   +  1/2 L I²

In this type of circuit, energy oscillates, which means that it is exchanging between both fields all time.

When the capacitor is completely discharged, all the energy is stored in the magnetic field, and at that time, the current is maximum.

The total energy, when I is maximum, can be written as follows:

E = 1/2 L I² (1)

In our case, when I= 2.4A, E= 56 mJ.

So, we can find out the value of L, which will allow us to know the value of the magnetic energy at any time, having the value of the instantaneous current.

Solving for L in (1):

L = 2 *.56 mJ / (2.4)² A² = 20 mH

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As the total energy must be always the same, i.e., 56 mJ, the energy stored in the capacitor, assuming no losses, must be the difference between the total energy and the one stored in the magnetic field:

Ec = 56 mJ - 14.4 mJ = 41.6 mJ

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3 years ago
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Brilliant_brown [7]
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