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levacccp [35]
3 years ago
6

The diagram is being used to illustrate the second law of thermodynamics, where Qh represents a hot object and Qc represents a c

old object.
A black box on the left labeled Q Subscript h Baseline and a touching white box on the right labeled Q Subscript c Baseline.

Which will best complete the diagram to illustrate the law?

adding in the boxes an arrow that points from Qh to Qc
adding in the boxes an arrow that points from Qc to Qh
adding in the boxes an arrow that points in both directions between Qh and Qc
adding in each box an arrow that points upward from Qh and from Qc

The correct answer is A. adding in the boxes an arrow that points from Qh to Qc
Physics
2 answers:
sdas [7]3 years ago
9 0

Answer:

Adding in the boxes an arrow that points from Q_{h} to Q_{c}.

Explanation:

According to the Second Law of Thermodynamics,<em> the heat transfer occur from a higher temperature body to a lower temperature body</em>.

So, applying the Second Law of Thermodynamics, the correct answer is the first one: Adding in the boxes an arrow that points from Q_{h} to Q_{c}; because this direction is pointing the right one, it doesn't violate the second law of the thermodynamics, the heat is gonna go from Q_{h} to Q_{c}, and the arrow indicates that.

Remember that the problem states that Q_{c} is a cold object and Q_{h} is a hot object.

katrin [286]3 years ago
6 0

Answer:

The answer is A. on edgen.

Explanation:

A. adding in the boxes an arrow that points from Qh to Qc

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Answer:

Explanation:

Thinking about the logics it can but it may be dim because 1.12 is lower than 2,5v so this will mean u lamp may not work or may work very dimely due to the low voltage it is receiving.

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nan moved 18m to the right and then another 22m to the right if the motion takes 20 seconds what is nans velocity
IrinaVladis [17]
Step 1: list known info

distance(change in position (Δx))= 18m+22m= 40m
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Step 2 :solve for velocity

velocity= Δx÷time
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Answer: the velocity is 2 meters per a second (m/s)


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3 years ago
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This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

<h3><u>Data:</u></h3>
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To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t.

We substitute the data in the formula: the <u>speed is equal to 4.6 m/s,</u> the <u>time is equal to 10 s</u>, which is left as follows:

\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }

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Therefore, the speed at 10 seconds is 46 meters.

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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