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Ivahew [28]
3 years ago
6

Which describes the force between two magnets when their south poles are almost touching?

Physics
2 answers:
Oliga [24]3 years ago
7 0
<span>Which describes the force between two magnets when their south poles are almost touching?

Answer: C, the poles strongly repel each other.

HOPE THIS HELPS! ^_^</span>
almond37 [142]3 years ago
3 0
The poles strongly repel each other
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What is an isotope?
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A

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A turtle and a rabbit are in a 150 meter race. The rabbit decides to give the turtle a 1 minute head start. The turtle moves at
yan [13]

Answer:

a) s_{T} = 30\,m, b) t = 5\,min, c) \Delta t = 6.667\,s, d) \Delta s_{R} = 33.333\,m, e) t' = 11.667\,s, f) The rabbit won the race.

Explanation:

a) As turtle moves at constant speed, its position is determined by the following formula:

s_{T} = v_{T}\cdot t

Where:

t - Time, measured in seconds.

v_{T} - Velocity of the turtle, measured in meters per second.

s_{T} - Position of the turtle, measured in meters.

Then, the position of the turtle when the rabbit starts to run is:

s_{T} = \left(0.5\,\frac{m}{s} \right)\cdot (60\,s)

s_{T} = 30\,m

The position of the turtle when the rabbit starts to run is 30 meters.

b) The time needed for the turtle to finish the race is:

t = \frac{s_{T}}{v_{T}}

t = \frac{150\,m}{0.5\,\frac{m}{s} }

t = 300\,s

t = 5\,min

The time needed for the turtle to finish the race is 5 minutes.

c) As rabbit experiments a constant acceleration until maximum velocity is reached and moves at constant speed afterwards, the time required to reach such speed is:

v_{R} = v_{o,R} + a_{R}\cdot \Delta t

Where:

v_{R} - Final velocity of the rabbit, measured in meters per second.

v_{o,R} - Initial velocity of the rabbit, measured in meters per second.

a_{R} - Acceleration of the rabbit, measured in \frac{m}{s^{2}}.

\Delta t - Running time, measured in second.

\Delta t = \frac{v_{R}-v_{o,R}}{a_{R}}

\Delta t = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{1.50\,\frac{m}{s^{2}} }

\Delta t = 6.667\,s

The time taken by the rabbit to reach maximum speed is 6.667 s.

d) On the other hand, the position reached by the rabbit when maximum speed is reached is determined by the following equation of motion:

v_{R}^{2} = v_{o,R}^{2} + 2\cdot a_{R}\cdot \Delta s_{R}

\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}

\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}

Where \Delta s_{R} is the travelled distance of the rabbit from rest to maximum speed.

\Delta s_{R} = \frac{\left(10\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(1.50\,\frac{m}{s^{2}} \right)}

\Delta s_{R} = 33.333\,m

The distance travelled by the rabbit from rest to maximum speed is 33.333 meters.

e) The time required for the rabbit to finish the race can be determined by the following expression:

t' = \frac{\Delta s_{R}}{v_{R}}

t' = \frac{150\,m-33.333\,m}{10\,\frac{m}{s} }

t' = 11.667\,s

The time required for the rabbit from rest to maximum speed is 11.667 seconds.

f) The animal with the lowest time wins the race. Now, each running time is determined:

Turtle:

t_{T} = 300\,s

Rabbit:

t_{R} = 60\,s + 6.667\,s + 11.667\,s

t_{R} = 78.334\,s

The rabbit won the race as t_{R} < t_{T}.

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3 years ago
In separate experiments, a large number of particles (all with the same charge, but with a wide variety of masses and speeds) ar
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Answer:

  they have the same mass

Explanation:

The force applied by the field is a function of the charge and velocity, so the acceleration experienced by a particle will be dependent upon its mass. Particles in orbits with the same radius are exhibiting the same acceleration, so must have the same mass.

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How much heat does it take to raise a<br> cup of water (2.34 x 10-4 m3) from<br> 15.0 °C to 75.0 °C?
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Answer:58600

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