Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Stephen Crane was both a novelist and a C. reporter, although he left that other job and became a full time writer.
The answer to this question would be:<span>D. delusions of grandeur.
Characteristics that are unique in schizophrenia is that they have delusion and hallucination. In schizotypal patient, they have a strange idea and behavior. Sometimes they also have an idea of reference. note that the schizotypal is a personality disorder so it is on a different axis than the schizophrenia.</span>
<span>Many species of sponges and the Hydra perform external budding. Cells will quickly divide within them and develop on the surface of the organism. These cells will form branches or extensions of the parent as they develop into a new organism.
i wish this helped</span>