Answer:
Pyruvic acid is not the end product of fermentation because in fermentation the pyruvic acid is converted into alcohol/lactic acid and carbon dioxide. There are two types of fermentation alcoholic fermentation and lactic acid fermentation.
In alcoholic fermentation, pyruvate is converted into ethanol and CO2 for example in yeast and in lactic acid fermentation pyruvate is converted into lactic acid and CO2 for example in animals muscles.
Therefore in fermentation pyruvic acid is not the end product of fermentation. In fermentation 2 ATP is produced.
Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:



So, if the population is in balance:



Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:



I hope you have a SUPER day!
It's B, Most them can make or produce their own food.
Water is important to some organism.... i think