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Maslowich
3 years ago
9

Lesson 14.2 Interpret graph boyles law

Chemistry
1 answer:
docker41 [41]3 years ago
6 0
As what we can see on the graph of the Boyle's Law, we can imply that volume and pressure are inversely proportional. The gas law furthermore explains that at this condition, the temperature must be held constant. The law can be furthermore be explained using the equation:

PV = k
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O2, oxygen.

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In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.

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Answer:

1 +1 = 2

(Just put this here so it doesn't get flagged)

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1 +1 = 2

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A combustion reaction involves only hydrogen, carbon, and oxygen where O2 is always a reactant. So, the only one possible is the one stated above.
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