Answer:
Note that the angle of lap is 165 degrees at the question above
So the power (kW) transmitted when the belt runs at 13 m/s and centrifugal force is included = 3.79782kW
Explanation:
Centrifugal force, Fc = pAv^2
Where p = density, A = c.s.a. v = veelocity
= 11x100 kg/m3 X 4x100 mm2 X (13 m/s)^2
= 1100 kg/m3 X 400 mm2 x 10^-6 X 169m/s
= 74.36N
P v (f - Fc) (1-e^-μθ)
The θ = (165 degrees ÷ 180 degrees) X π = 2.878 rads (π = 3.14)
So power p, = 10 (637 N - 74.36N) (1 - e^-0.39 x 2.878)
= 10 X 562.64 X 0.675
P = 3797.82 watts = 3.79782kW
Depends how far you live from your friend
A hanging mass of 23 kg will exert a force of:
23 * 9.81 = 225.6 Newtons on the string
Thus, during rotation, the force exerted should remain less than this. Force on an object in circular motion is given by:
F = (m * v^2) / r
225.6 = (2.95 * v^2) / 0.791
v = sqrt(60.491)
v = 7.78 m/s
Thus, the magnitude of the velocity should not exceed 7.78 meters per second.
Answer:
a)
b)
Explanation:
a)
Using the conservation of energy between the moment when the bullet hit the block and the maximum compression of the spring.
Where:
- M is the bullet-block mass (0.00535 kg + 2.174 kg = 2.17935 kg)
- V is the speed of the system
- k is the spring constant (6.17*10² N/m)
- Δx is the compression of the spring (0.0634 m)
Then, let's find the initial speed of the bullet-block system.
b)
Using the conservation of momentum we can find the velocity of the bullet.
I hope it helps you!