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Jobisdone [24]
3 years ago
10

Two cars travel on a straight road from point A to point B. Both cars accelerate to their maximum speed and then continue at tha

t speed for the rest of the distance. Car 1 accelerates from rest to 20 m/s over 30 s. It reaches point B in 35 s. Car 2 accelerates from rest to 20 m/s over 20 s. It reaches point B in 30 s. Which car uses a larger acceleration to reach its maximum speed, and which car has a larger average speed?
A) Car 1 has both a larger acceleration and a larger average speed.

B) Car 2 has both a larger acceleration and a larger average speed.

C) Car 1 has a larger acceleration, but Car 2 has a larger average speed.

D) Car 2 has a larger acceleration, but Car 1 has a larger average speed.
Physics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

B) Car 2 has both a larger acceleration and a larger average speed.

Explanation:

Car 2 reaches 20 m/s faster than Car 1, so it has a larger acceleration.  Car 2 also reaches point B faster than Car 1, so it has the higher average speed.

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Please help me do this problem
Digiron [165]

Answer:

i) acceleration from B to D is 0, because the velocity is constant (stays the same)

ii) whatever units of distathat might be, we can calculate the number:

for 4 time-steps (2 to 6) the velocity is 6 per time step, that makes 24 distance units in these 4 time steps. it's the same the area underneath the graph.

there is also the vertical line from 0 to 2. we can calculate that distance like the area of a triangle with 2*6 / 2 = 6

the total distance from 0 to D is therefore 30

4 0
3 years ago
PUBLIC SCHOOLS
padilas [110]

Answer:

D. The cart is moving at a constant speed or velocity

Explanation:

Equilibrium is a state of body in which it is either at rest or moves with uniform velocity. The sum of forces acting on such a body is always zero and the sum of all the torques acting on it is also zero.

There are two types of equilibrium as follows:

Static Equilibrium: When a body is at rest it is said to be in static equilibrium.

Dynamic Equilibrium: When a body is moving with constant velocity, then it is said to be in dynamic equilibrium.

Hence, the correct option here will be:

<u>D. The cart is moving at a constant speed or velocity</u>

4 0
3 years ago
A single conservative force acts on a 5.30-kg particle within a system due to its interaction with the rest of the system. The e
cupoosta [38]

Answer:

Given that

m = 5.3 kg

Fx = 2x + 4

We know that work done by force F given as

w= ∫ F. dx

a)

Given that x=1.08 m to x=6.5 m

Fx = 2x + 4

w= ∫ F. dx

w=\int_{1.08}^{6.5}(2x+4) .dx

w=\left [x^2+4x \right ]_{1.08}^{6.5}

w=(6.5^2-1.08^2)+4(6.5-1.08)\ J

w=62.7 J

b)

We know that potential energy given as

F=-\dfrac{dU}{dx}

∫ dU =  -∫F.dx           ( w= ∫ F. dx)

ΔU= -62.7 J

c)

We know that form work power energy theorem

Net work = Change in kinetic energy

W= KE₂ - KE₁

62.7 =KE₂ - (1/2)x 5.3 x 3²

KE₂ = 86.55 J

This is the kinetic energy at 6.5m

8 0
3 years ago
A tissue box has regular dimensions
vova2212 [387]

Considering the volume of a rectangle, the volume of the tissue box is 3,239.1 cm³.

<h3>What is volume</h3>

Volume is a scalar-type metric quantity that is defined as the extension in three dimensions of a region of space. In other words, the volume corresponds to the space that the shape occupies.

<h3>Volume of a rectangle</h3>

To calculate the volume of a rectangle, it is necessary to multiply its 3 dimensions: length ×width×height. Volume is expressed in cubic units.

<h3>Volume of the tissue box</h3>

In this case, you know:

  • Length: 11.8 cm
  • Width: 12.2 cm
  • Height: 22.5 cm

Replacing in the definition of volume of a rectangle:

Volume of the tissue box= length ×width×height

Volume of the tissue box= 11.8 cm× 12.2 cm× 22.5 cm

Solving:

<u><em>Volume of the tissue box= 3,239.1 cm³</em></u>

Finally, the volume of the tissue box is 3,239.1 cm³.

Learn more about volume:

brainly.com/question/13535768

brainly.com/question/21172800

#SPJ1

5 0
2 years ago
Which of the following would decrease in size during the contraction of a sarcomere? The width of the I-bands The width of the A
ANEK [815]

Hi!


The correct answer would be: the width of I-bands


The sacromere is the smallest contractile unit of striated muscles. These units comprise of filaments (fibrous proteins) that, upon muscle contraction or relaxation, slide past each other. The sacromere consists of thick filaments (myosin) and thin filaments (actin).


<em>Refer to the attached picture to clearly see the structure of a sacromere.</em>


<u>When a sacromere contracts, a series of changes take place which include:</u>

<em>- Shortening of I band, and consequently the H zone</em>

<em>- The A line remains unchanged</em>

<em>- Z lines come closer to each other (and this is due to the shortening of the I bands) </em>

The only changes that take place occur in the zones/areas in the sacromere (as mentioned), not in the filaments (actin and myosin) that make the up the sacromere; hence all other options are wrong.


Hope this helps!

8 0
3 years ago
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