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3 years ago

6

A jeweller paid $6800 for 165 bracelets bought in China .The customs Department in his country charged him $1360 in duty

1 answer:

Troyanec [42]3 years ago

8 0

You’re so smart, I love questions like this. Hopefully you can solve it so I can know too!

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Please Help Find the indicated side of the right triangle

andrew11 [14]

Answer:

3 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan 60 = x/3

3 tan 60 = x

3 sqrt(3) = x

7 0

3 years ago

Read 2 more answers

A circle has a CIRCUMFERENCE of 6.<br><br> What is it's DIAMETER?<br><br> thank you!

kati45 [8]

C = pi * d
d = C / pi
d = 6 / 3.14
d = 1.91 units

6 0

2 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

2 years ago

Could someone help me arrange these pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (2

Zina [86]

Answer:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

Step-by-step explanation:

Required

Arrange in increasing order of slope

Slope (m) is calculated using:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

(a) (15, 30) and (20, 40)

$m = \frac{40 -30}{20- 15}$

$m = \frac{10}{5}$

$m =2.00$

(b) (12, 32) and (18, 48)

$m = \frac{48 -32}{18- 12}$

$m = \frac{16}{6}$

$m = 2.67$

(c) (27, 12) and (72, 32)

$m = \frac{32-12}{72- 27}$

$m = \frac{20}{45}$

$m = 0.44$

(d) (45, 15) and (60, 20)

$m = \frac{20-15}{60- 45}$

$m = \frac{5}{15}$

$m = 0.33$

(e) (27, 2) and (243, 18)

$m = \frac{18-2}{243- 27}$

$m = \frac{16}{216}$

$m = 0.07$

(f) (18, 63) and (24, 84)

$m = \frac{84-63}{24- 18}$

$m = \frac{21}{6}$

$m = 3.50$

(g) (63, 9) and (84, 12)

$m = \frac{12 -9}{84- 63}$

$m = \frac{3}{21}$

$m = 0.14$

From least to greatest slope, the pair of points are:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

6 0

2 years ago

rope price of length 45cm 25 cm and 81 cm have to be cut into same size pieces what is the smallest price length possible

Sergeeva-Olga [200]

= 2025

When you are told to find the smallest length possible, you perform L.C.M(Least common multiples)

For this, you divide the given lengths using the numbers that divides all through.

I have added an image to this answer. Go through it for more explanation

5 0

2 years ago