The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.
The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.
Now, we will consider each reaction individually to decode whether or not a precipitate is possible.
- In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
- In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
- In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.
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Answer:
2+
Explanation:
The charge on Z in the compound ZB₂ is a 2+
From the given compound:
We know that Br is bromine with a charge of -1;
So;
Using the combining power approach:
Atoms Z Br
Combining power 2 1
Exchange of valency 1 2
So;
The charge on Z is 2+
2
Hey, what's the question asking you to solve for?
The answer i think is 5.0
Answer: Option C is not a property of a acid, acids turn blue litmus paper red.
Explanation: