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ElenaW [278]
2 years ago
8

Solve the system of equations: y=2x y=x²-8

Mathematics
1 answer:
igomit [66]2 years ago
6 0
Set equal to each other
x^2 - 8 = 2x
x^2 - 2x - 8 = 0

Factor
(x - 4)(x + 2) = 0
x = 4 or x = -2

Plug in 4
y = 2x or y = x^2 - 8
y = 2(4) or y = 4^2 - 8
y = 8

Plug in -2
y = 2x or y = x^2 - 8
y = 2(-2) or y = (-2)^2 - 8
y = -4

There are two solutions
(4, 8) and (-2, -4)
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Evaluate [16 ÷ (2 + 3 • 2)] + [4 • (36 – 25)]
maw [93]

Answer:

46

Step-by-step explanation:

There is an open + in the middle. It does not have any brackets around it. Therefore you do it at the very last.

Left side of the plus sign.

[16 ÷ (2 + 3*2)] Do the multiplication inside the parenthesis ( 2*3) first.

= [16 ÷ (2 + 6)] Add inside the parenthesis.

= [16 ÷ 8 ]         Do the division

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Right side of the open plus sign

[4 * (36 - 25)]   Do the subtraction first.

[4 * 11 ]             Do the multiplication

44

Now combine both right and left side.

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8 0
3 years ago
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jek_recluse [69]

Answer:

D for both

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Can you help me to solve this​
Ber [7]

Answer:

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Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

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= (2a + 1)²

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= \frac{2(2a-1)}{2a+1}

= \frac{4a-2}{2a+1}

3 0
3 years ago
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