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2 years ago

Which object would a geologist date using carbon-14 dating?

2 answers:

6 0

Radiocarbon dating involves determining the age of an ancient fossil or specimen by measuring its carbon-14 content. ... Green plants absorb the carbon dioxide, so the population of carbon-14 molecules is continually replenished until the plant dies. Carbon-14 is also passed onto the animals that eat those plants.

The radiocarbon dating, also referred to as carbon -14 dating, is used for the determining of the age of an object containing organic matter based on the properties of the radiocarbon.
The age detection of the ancient objects are very tough,due to no records are available about the objects.
That's why scientists use carbon-14 dating process.
In this picture, the only object that contains organic material is the animal skull, thus it is the only one that can be dated with this method.

Read more on Brainly.com - brainly.com/question/13226687#readmore

alexira [117]2 years ago

3 0

Answer:

The correct answer is - the first object, the animal skull. The radiocarbon dating, also referred to as carbon -14 dating, is used for the determining of the age of an object containing organic matter based on the properties of the radiocarbon.

Explanation:

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ANTONII [103]

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2 years ago

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The rate constant for a first-order reaction is 2.4 x 10-4 L/(mol's) at 600 K and 6.2 x 10-4L/(mol · s) at 900 K.

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Answer:

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3 years ago

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A gas system contains 2.00 moles of O2 and CO2 gas, has an initial temperature of 25.0 oC and is under 1.00 atm of pressure. If

Ainat [17]

Answer:

$V_2=52.2L$

Explanation:

Hello there!

In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:

$PV=nRT\\\\V=\frac{2.00mol*0.08206\frac{atm*L}{mol*K}*298.15K}{1.00 atm} \\\\V=48.9L$

Which is V1 in the Charles' law:

$\frac{T_2}{V_2} =\frac{T_1}{V_1}$

And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:

$V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{48.9L*(45+273.15)K}{(25+273.15)K} \\\\V_2=52.2L$

Best regards!

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3 years ago