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liq [111]
3 years ago
11

Which object would a geologist date using carbon-14 dating?

Chemistry
2 answers:
lidiya [134]3 years ago
6 0
Radiocarbon dating involves determining the age of an ancient fossil or specimen by measuring its carbon-14 content. ... Green plants absorb the carbon dioxide, so the population of carbon-14 molecules is continually replenished until the plant dies. Carbon-14 is also passed onto the animals that eat those plants.


The radiocarbon dating, also referred to as carbon -14 dating, is used for the determining of the age of an object containing organic matter based on the properties of the radiocarbon.
The age detection of the ancient objects are very tough,due to no records are available about the objects.
That's why scientists use carbon-14 dating process.
In this picture, the only object that contains organic material is the animal skull, thus it is the only one that can be dated with this method.

Read more on Brainly.com - brainly.com/question/13226687#readmore
alexira [117]3 years ago
3 0

Answer:

The correct answer is - the first object, the animal skull. The radiocarbon dating, also referred to as carbon -14 dating, is used for the determining of the age of an object containing organic matter based on the properties of the radiocarbon.

Explanation:

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Answer: the acid

Explanation:

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4 years ago
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
0.65 moles of O2 originally at 85°C is cooled
soldier1979 [14.2K]

Answer:

2.09 atm

Explanation:

We can solve this problem by using the equation of state for an ideal gas, which relates the pressure, the volume and the temperature of an ideal gas:

pV=nRT

where

p is the pressure of the gas

V is its volume

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R is the gas constant

T is the absolute temperature

In this problem we have:

n = 0.65 mol is the number of moles of the gas

V = 8.0 L is the final volume of the gas

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Solving for p, we find the final pressure of the gas:

p=\frac{nRT}{V}=\frac{(0.65)(0.082)(313)}{8.0}=2.09 atm

8 0
4 years ago
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PIT_PIT [208]

For the answer to the question above,
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7 0
3 years ago
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3 0
3 years ago
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