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Whitepunk [10]
2 years ago
10

How many atoms of fluorine are present in a molecule of carbon tetrafluoride CF4

Chemistry
1 answer:
Daniel [21]2 years ago
3 0
There are 4, 1 Carbon 4 Fluorine 
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In sediments and waterlogged soil, dissolved O2 concentrations are so low that the microorganisms living there must rely on othe
kakasveta [241]

Answer:

1) SO₄ ²⁻ : (+6)

  H₂S : (-2)

Explanation:

a) <u>Sulfate reducers</u> are widespread in muds and other sediments, water-logged soils, etc., environments that contain SO₄ ²⁻ and become anoxic as a result of microbial decomposition.

Sulfate (SO₄ ²⁻), the most oxidized form of sulfur (+6), <u>is reduced</u> by these

sulfate-reducing bacteria. The end product of sulfate reduction is hydrogen sulfide, H₂S, (oxidation number -2) an important natural product that participates in many biogeochemical processes. The H₂S they generate is responsible for the pungent smell (like that of rotten eggs) often encountered near coastal ecosystems. When sulfate-reducing bacteria grow, the H₂S formed from SO₄ ²⁻ reduction combines with the ferrous iron to form black, insoluble ferrous sulfide, which is not toxic. This is important for the conservation of the environment.

b) The net ionic equation under acidic conditions is:

              4 H₂ + SO₄²⁻ + H⁺ → HS⁻ + 4 H₂O

    Global reaction:  SO₄²⁻ + 2H⁺ → H₂S + O₂

3 0
2 years ago
A standard room temperature and pressure, most of the elements on the periodic table are
IgorC [24]
Gasses i’m pretty sure.
6 0
2 years ago
Read 2 more answers
Colligative property definition chemistry
Vadim26 [7]

Answer: Colligative properties are those properties of solutions that are dependent on the concentration of the solutes in the solution.

Colligative properties has to do with solutions, that is, solutes that are dissolved in solvents. Examples of colligative properties are: freezing point depression, vapour pressure lowering, boiling point elevation and osmotic pressure. Colligative properties do not depend on the identity of the solutes, this implies that the effect of colligative properties are uniform across all solutions. For example, the freezing point depression of any solution will depend on the concentration of solutes that are dissolve in solution.

4 0
3 years ago
What cell part is NOT found in all cells?
elena-s [515]

Answer:

heart I think also I'm so sorry if I get you this wrong I think membrane not sure tell me what was the right answer but I think membrane.

3 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
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